Borrar filtros
Borrar filtros

Converge a 1x30 row vector to a 3x10 matrix

4 visualizaciones (últimos 30 días)
Wietze Zijpp
Wietze Zijpp el 5 de Abr. de 2022
Comentada: Voss el 6 de Abr. de 2022
Suppose I have the following
z = [1:30]
Now I want to create a 3x 10 matrix. Where the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30

Respuesta aceptada

Wietze Zijpp
Wietze Zijpp el 5 de Abr. de 2022
Editada: Torsten el 5 de Abr. de 2022
I have found the solution
Use
mymat = reshape(z,3,10)
  1 comentario
Voss
Voss el 6 de Abr. de 2022
"the entries in the first row are the first 10 values. In the second row entries 11:20 and in the third row 21:30"
If you want the order like that, you have to do it differently:
z = 1:30;
mymat = reshape(z,3,10)
mymat = 3×10
1 4 7 10 13 16 19 22 25 28 2 5 8 11 14 17 20 23 26 29 3 6 9 12 15 18 21 24 27 30
mymat = reshape(z,10,3).'
mymat = 3×10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrices and Arrays en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by