For loop and omitting every 10th step

Hello,
I am doing some Bayesian by running a Gibbs sampler. My issue is that I would like to omit (drop) the draws I get in every 10th repetition. So I was wondering whether there is any command or trick while I am using the FOR command, to ignore or jump the every 10th repetition. So for example:
for i=1:30
I would i to take values 1 2 3 4 5 6 7 8 9 11 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 29
Any idea? Many thanks

1 comentario

Stephen23
Stephen23 el 20 de En. de 2015
You should not use i or j as the loop variable name, as these are the names of the inbuilt imaginary unit .

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 Respuesta aceptada

Image Analyst
Image Analyst el 20 de En. de 2015
for i = 1 : 30
if rem(i, 10) == 0
continue;
end
end

6 comentarios

Yet another way:
indexesToUse = [1 2 3 4 5 6 7 8 9 11 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 29]
for i = indexesToUse
fprintf('i = %d\n', i);
end
Panty
Panty el 20 de En. de 2015
Clever answer..Thanks you very much 'Image'
Panty
Panty el 20 de En. de 2015
Image, Inside my initial 'for' command I have other loops and calculations. How should I write the above trick, so that any time i=10,20,30 everything that is inside my 'for' loop be ignored.
Image Analyst
Image Analyst el 20 de En. de 2015
Either of those methods will work. The first one goes through all i but then skips to the end if it hits 10, 20, 30. Put your code after the if block. The second code never even takes on the values 10, 20, 30 so there is no problem, just put your code inside the loop.
So if I do it like:
for i = 1 : 30
if rem(i, 10) == 0
continue;
end
for p=1:10
....
end
k=k+1
end
So if i=10,20 or 30 then neither "for p=1:10" nor "k=k+1" will execute. Correct?
Image Analyst
Image Analyst el 20 de En. de 2015
Correct.

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Más respuestas (2)

David Young
David Young el 20 de En. de 2015
for i = floor(1:10/9:30)
...
end

2 comentarios

Panty
Panty el 20 de En. de 2015
Thank you very much David for the help. It seems clever as well.
Stephen23
Stephen23 el 20 de En. de 2015
Editada: Stephen23 el 20 de En. de 2015
Do not use i as the loop variable name, as this is the name of the inbuilt imaginary unit .

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Stephen23
Stephen23 el 20 de En. de 2015
A = 1:30;
A(10:10:end) = [];
for a = A
....
end

1 comentario

Panty
Panty el 21 de En. de 2015
Thank you Stephen. It looks helpful as well.

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