Using interp1 with semilog dataset

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Alex
Alex el 31 de Ag. de 2022
Editada: Alex el 31 de Ag. de 2022
I have 3 arrays:
  • 'Dose' contains 27 values ranging from 1x10^2 to 1x10^6
  • 'AlThick' contains 27 values ranging from 0.0001 to 20
  • 'Rays' contains 10000 values ranging from 0 to 20
The points in each data set are not equally spaced. Dose represents y values; AlThick and Rays both represent x values. I want to find the value of Dose for each non-zero value of Rays. I am doing the following and getting, as expected, 10000 values.
DoseMat = interp1(AlThick, Dose, rays(rays>0), 'linear')
However, I'm not sure if I need to be accounting for the fact that the y-axis data is plotted as a base-10 logarithm. I.e. it is a semilog plot with base-10 log values on the y-axis and linear values on the x-axis, as shown below.
Any advice is appreciated!
  2 comentarios
Torsten
Torsten el 31 de Ag. de 2022
Editada: Torsten el 31 de Ag. de 2022
And plotting "Dose" against "AlThick" in semilogy gives you a linear relationship ?
Could you include this plot ?
Alex
Alex el 31 de Ag. de 2022
I have updated the OP with the plot of Dose vs AlThick

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Respuesta aceptada

Cris LaPierre
Cris LaPierre el 31 de Ag. de 2022
Editada: Cris LaPierre el 31 de Ag. de 2022
You do not need to take account of the fact that you are plotting your data in a semilog plot. That doesn't impact how you would interpolate the data. The 'linear' here is the interpolation method.
However, you are not using interp1 correctly. Interp1 is for (x,y) data. The syntax is
  • newY = interp1(knownX, knownY, newX, method).
You probably want to use interp2.
  • newZ = interp1(knownX, knownY, knownZ, newX, newY, method).
  4 comentarios
Image Analyst
Image Analyst el 31 de Ag. de 2022
@Alex, attaching data in a .mat file, and screenshots of it plotted, would help.
Alex
Alex el 31 de Ag. de 2022
I've updated the OP with the plot of Dose vs AlThick

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