Problems clustering with kmeans
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I have a data set that is x,y,v. Each vector is quite long, ~2 million rows. Also, the data is scattered, i.e. not at regular x,y intervals/spacings. An x-y plot of a small section is included here. When plotting x-y you can see groupings of 9 data points each. There will be ~200K of these groupings. I need to cluster the data set and get an average v value for each cluster of 9 points.
I have used kmeans clustering:
[idx,CC] = kmeans([x,y],round(length(x)/9),'Replicates',10,'Options',statset('UseParallel',1));
This works for maybe 66% of the clusters. In other words, about 66% of the clusters it finds are composed of 9 data points as desired. The other clusters are somewhat smaller or larger in the amount of data points comprising them. Also attached is a histogram of the amounts of data points in the clusters that kmeans returns. The large peak at 9 is what I want and is 66% of the total values...
If I know how many points should be in each cluster (9) and I know the intra-point distance within the cluster (because the spacing of the 9 data points within a cluster is constant), is there a way to improve upon these results of kmeans? Can I stipulate that a cluster must have 9 points within it? Can I stipulate that a cluster can have a distance between its members that is no more than a prescribed value?
Other things I'm considering is looping over a kmeans calculation and each time just keeping the clusters that have the 9 points--repeating the kmeans for the data set with those entries removed. This may work but it seems there should be a better way considering I know a decent amount about the data structure.
Thanks for any suggestions!
5 comentarios
the cyclist
el 1 de Sept. de 2022
Can you upload the data in a MAT file?
Paul Safier
el 1 de Sept. de 2022
Paul Safier
el 2 de Sept. de 2022
the cyclist
el 3 de Sept. de 2022
Editada: the cyclist
el 3 de Sept. de 2022
Glad it worked out for you.
I'm curious what inputs worked for you, using dbscan (and if success seemed dependent on getting them right).
Paul Safier
el 3 de Sept. de 2022
Respuesta aceptada
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