How to generate a specific number of values within a range ?
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Majid
el 13 de Sept. de 2022
Comentada: Majid
el 13 de Sept. de 2022
Hi all!
I'm really wondering how to solve this problem: I have an initial matrix Q (100*60), I extracted the first and second non-zero values in each row using this command line
R = size(Q,1);
First_second_ele = zeros(R,2);
for k = 1:R
tmp = nonzeros(qm(k,:)); %extraction first and second element
idx = 1:min(2,numel(tmp));
First_second_ele(k,idx) = tmp(idx);
end
after this , i got two column vectors. Now i want to see 60 elements between the two extracted values.
for example the first two element are :
4.0000 5.3333
i used :
A=linspace(4.0000,5.3333,60);
the result :
A = 4.0000 4.0226 4.0452 4.0678 4.0904 4.1130 4.1356 4.1582 4.1808 4.2034 4.2260 4.2486 4.2712 4.2938 4.3164 4.3390 4.3616 4.3842 4.4068 4.4294 4.4520 4.4746 4.4972 4.5198 4.5424 4.5650 4.5876 4.6102 4.6328 4.6554 4.6779 4.7005 4.7231 4.7457 4.7683 4.7909 4.8135 4.8361 4.8587 4.8813 4.9039 4.9265 4.9491 4.9717 4.9943 5.0169 5.0395 5.0621 5.0847 5.1073 5.1299 5.1525 5.1751 5.1977 5.2203 5.2429 5.2655 5.2881 5.3107 5.3333
How can i do a loop to get the result of all rows?
2 comentarios
Image Analyst
el 13 de Sept. de 2022
Do you want the 60 values to be linearly spaced, or randomly spaced. Not sure what "the result of all rows" is, but you can access each element in A in a for loop like this
for k = 1 : numel(A)
thisAValue = A(k);
% Now do something with thisAValue.
end
Or do you want to interpolate with interp1 to get values of your other array between the two values and then insert those 60 new values into your existing Q matrix somewhere?
Respuesta aceptada
Jan
el 13 de Sept. de 2022
R = size(Q,1);
First_second_ele = zeros(R,2);
Y = zeros(R, 60);
for k = 1:R
tmp = nonzeros(qm(k,:)); %extraction first and second element
idx = 1:min(2,numel(tmp));
First_second_ele(k,idx) = tmp(idx);
if numel(idx) == 2
Y(k, :) = linspace(tmp(1), tmp(2), 60);
end
end
Más respuestas (1)
David Hill
el 13 de Sept. de 2022
a=sort(rand(10,2),2);
A=[];
for k=1:size(a,1)
A=[A;linspace(a(k,1),a(k,2),60)];
end
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