Respuesta aceptada

Voss
Voss el 13 de Dic. de 2022
% your matrix:
i = 0; m = 1; j = 2; n = 3;
M = repmat([i i i m m j j j n n],4,1)
M = 4×10
0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3
% delete columns 4-5 and 9-10:
M(:,[4 5 9 10]) = []
M = 4×6
0 0 0 2 2 2 0 0 0 2 2 2 0 0 0 2 2 2 0 0 0 2 2 2

4 comentarios

Sourasis Chattopadhyay
Sourasis Chattopadhyay el 14 de Dic. de 2022
How can i mak it in a loop for (m*n) matrix?
Voss
Voss el 14 de Dic. de 2022
Why do you want to do that?
Sourasis Chattopadhyay
Sourasis Chattopadhyay el 14 de Dic. de 2022
Because my matrix size is not fixed. But every time I need to delete two column after the equal number of column interval.
Suppose you want to delete columns 4, 9, 14, ... and columns 5, 10, 15, ...
M = reshape(1:100,4,[])
M = 4×25
1 5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 65 69 73 77 81 85 89 93 97 2 6 10 14 18 22 26 30 34 38 42 46 50 54 58 62 66 70 74 78 82 86 90 94 98 3 7 11 15 19 23 27 31 35 39 43 47 51 55 59 63 67 71 75 79 83 87 91 95 99 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 64 68 72 76 80 84 88 92 96 100
spacing = 5;
N_Cols = size(M,2);
col_to_delete = [4:spacing:N_Cols 5:spacing:N_Cols];
M(:,col_to_delete) = []
M = 4×15
1 5 9 21 25 29 41 45 49 61 65 69 81 85 89 2 6 10 22 26 30 42 46 50 62 66 70 82 86 90 3 7 11 23 27 31 43 47 51 63 67 71 83 87 91 4 8 12 24 28 32 44 48 52 64 68 72 84 88 92
No loop necessary.

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