3D matrix transpose and dimensioning

When I take the pagetranspose of the matrix I, which has the size shown in Fig. 1 below, I get the matrix "Itilde", which has the size shown in Fig. 2. But I want the size of each cell of the Itilde matrix to be 29x64. Below, the cells in a single column are 29x64x4. How can I divide it into 4 columns and make the size of each cell 29x64 as shown in Fig. 3?

Fig .1

Fig.2

Fig.3

Thanks.

[Steven Lord]

When I take the pagetranspose of the matrix I, which has the size shown in Fig. 1 below, I get the matrix "Itilde", which has the size shown in Fig. 2.

The pagetranspose function does not change a double array (your original matrix, shown in Fig. 1) into a cell array (Fig. 2). Therefore your code performs some other operation that you're not showing us. If you show us that operation we may be able to help you modify it to achieve your goal.

Answer 1

[KSSV]

% Data for demo 
A{1,1} = rand(3,3,3) ;
A{2,1} = rand(3,3,3) ;
A{3,1} = rand(3,3,3) ;
A{4,1} = rand(3,3,3) ;
A

A = 4×1 cell array
    {3×3×3 double}
    {3×3×3 double}
    {3×3×3 double}
    {3×3×3 double}

% Conversion 
B = cell(4,3) ;
for i = 1:4
    for j = 1:3
        B{i,j} = A{i}(:,:,j) ;
    end
end
B

B = 4×3 cell array
    {3×3 double}    {3×3 double}    {3×3 double}
    {3×3 double}    {3×3 double}    {3×3 double}
    {3×3 double}    {3×3 double}    {3×3 double}
    {3×3 double}    {3×3 double}    {3×3 double}

[Vecihi He]

This is exactly the answer I was looking for thank you very much :)

[KSSV]

Thanks is accepting the answer.. :)