how to create matrix c, where first column is vector a, and the last column is vector b without a loop
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
%if
a=[1;2;3;4;5];
%and
b=a+3;
%then how can i make a matrix c without a loop, but the result would be like the result of this loop?
for i = 1:5
c(i,:)=a(i,1):b(i,1);
end
0 comentarios
Respuesta aceptada
Voss
el 3 de Feb. de 2023
a = [1;2;3;4;5];
N = 3;
c = a+(0:N)
2 comentarios
Les Beckham
el 3 de Feb. de 2023
Nice!
Expanding on this idea for an arbitrary dimension square result:
N = 10; % desired dimension
a = 1:N;
c = a' + (0:(N-1))
Más respuestas (1)
Les Beckham
el 3 de Feb. de 2023
Editada: Les Beckham
el 3 de Feb. de 2023
a = [1;2;3;4;5];
c = [a a+1 a+2 a+3]
If you are a beginner in using Matlab, I would suggest taking a couple of hours to go through the free tutorial that can be found here: Matlab Onramp
2 comentarios
Les Beckham
el 3 de Feb. de 2023
Editada: Les Beckham
el 3 de Feb. de 2023
I can't seem to come up with a way to do that without a loop. Assuming the result is supposed to be square, this should work and seems a bit more clear to me than your loop solution.
N = 10; % desired dimension
a = 1:N;
for i = 1:N
c(i,:) = a + i - 1;
end
disp(c)
Note that this will create the upper triangular part of the matrix, but I couldn't figure out how to generate the lower half.
c = hankel(1:N)
Ver también
Categorías
Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!