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How to do the following two for loop?

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M
M el 9 de Feb. de 2023
Comentada: M el 10 de Feb. de 2023
How to do the following two for loop?
i=0.1:0.1:0.9 ;
M=[1 1 1 1 1 1];
first outer loop :
In the 1st inner loop Assign i=0.9 on the first element, then in the 2nd inner loop Assign 0.8 on the first element till 0.1
then 2nd outer loop
In the 1st inner loop Assign i=0.9 on the 2nd element, in the 2nd inner loop Assign 0.8 on the 2nd element till 0.1
.
.
and so on .. till the 6th outer loop

Respuesta aceptada

Torsten
Torsten el 9 de Feb. de 2023
You mean
i=0.1:0.1:0.9 ;
M = [i.',ones(numel(i),5)]
M = 9×6
0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
?
  9 comentarios
Torsten
Torsten el 10 de Feb. de 2023
Editada: Torsten el 10 de Feb. de 2023
That's exactly what the code does (see above).
Or do you want the element of the outer loop remain at 0.1 instead of resetting it to 1 ?
Then delete the line
M(i) = 1.0;
M
M el 10 de Feb. de 2023
@Torsten yes i deleted that line and now its working good. Thanks

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Más respuestas (2)

Image Analyst
Image Analyst el 9 de Feb. de 2023
Don't call variables "i" -- it's the imaginary constant.
Try this, for example to multiply M by 2
vec = 0.1:0.1:0.9
vec = 1×9
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000
M = [vec 1 1 1 1 1]
M = 1×14
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
result = M * 2
result = 1×14
0.2000 0.4000 0.6000 0.8000 1.0000 1.2000 1.4000 1.6000 1.8000 2.0000 2.0000 2.0000 2.0000 2.0000
% Or via a for loop
for k = 1 : numel(vec)
result(k) = 2 * M(k);
end
To learn other fundamental concepts, invest 2 hours of your time here:

Image Analyst
Image Analyst el 10 de Feb. de 2023
"assign i=0.9 on the first element, then assign 0.8 on the first element till 0.1"
Try this
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
result
result = 1×9
0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000
  2 comentarios
M
M el 10 de Feb. de 2023
I want to move into M=[i 1 1 1 1 1], it is an input for another function
Image Analyst
Image Analyst el 10 de Feb. de 2023
OK, so did you do it? Again, don't use "i" as the name of your variable. That is something everyone here advises against.
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
M = [result, 1 1 1 1 1]

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