Hi!
I have a situation in my code like this:
a = b+c ~= d/e;
where a, b, c, d and e are real numbers, but I don't know what this expression means...
Can you help me, please?
Thank you! :D

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Voss
Voss el 4 de Mzo. de 2023

0 votos

a = b+c ~= d/e;
for scalars b, c, d, and e, is the same as
if b+c ~= d/e
a = true;
else
a = false;
end

6 comentarios

Note that ~= has a low priority, so the code is interpreted as
(b+c) ~= (d/e)
Laura Costa Pereira Miranda
Laura Costa Pereira Miranda el 6 de Mzo. de 2023
Thank you Voss and Walter for the answers!
But, in this case, if a is true (or false), a will have just this binary value? Because, when I display the value of a, this variable assumes a real value.
I'm still confuse about it.
And thank you a million for the answers! <3
Yes, a will be either true or false. a will be a logical scalar.
When you display a, true is represented as a 1 and false is represented as a 0:
a = true
a = logical
1
a = false
a = logical
0
But notice they are of class logical, not double (or some other numeric class).
However, if you use a in a calculation, the value 0 or 1 will be used:
a = true;
result = a+4 % true+4 is interpreted as 1+4
result = 5
a = false;
result = false*8 % false*8 is interpreted as 0*8
result = 0
and result is of class double (the default numeric class):
class(result)
ans = 'double'
Laura Costa Pereira Miranda
Laura Costa Pereira Miranda el 6 de Mzo. de 2023
Oh! I understand now! It makes sense :D
Thanks a million!!
Voss
Voss el 6 de Mzo. de 2023
You're welcome!
By the way, in the context of if or while then an expression is considered true if the expression evaluates to something that is all non-zero (if it evaluates to contain nan then you will get an error)
if -3:2:5; disp('yep okay'); else disp('nope'); end
yep okay
if -4:2:4; disp('yep okay'); else disp('nope'); end
nope
The first one is completely non-zero but the second one contains at least one zero.

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