randomAffine3d() claim to take function handle for shear, but parser fails it

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Mads el 24 de Mzo. de 2023
According to the doc of randomAffine3d:
Shear Range of shear
[0 0] (default) | 2-element numeric vector | function handle
...
A function handle. The function must accept no input arguments and return the shear angle as a numeric scalar. Use a function handle to pick a shear angle from a disjoint interval or using a nonuniform probability distribution.
When using this function e.g.
function A = selectShear1
A = -(rand(1,1)*5+5);
end
the validator (below) returns with this error message:
'The value of 'Shear' is invalid. Expected Shear to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64
which seems to be alright given:
function TF = validateShear(val)
iValidateNumericRange('Shear',val,'<',90,'>',-90);
TF = true;
end
That it after all doesn't take function handles...
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Steven Lord el 24 de Mzo. de 2023
Can you show us the code you've written to call randomAffine3d using this function handle?

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Respuestas (1)

Mads el 24 de Mzo. de 2023
for ro = [0,-1,1]
if ro == -1
Rot = @selectRotation1;
elseif ro == 0
Rot = [0,0];
elseif ro == 1
Rot = @selectRotation2;
end
for sh = [0,-1,1]
if sh == -1
She = [-10,-5];%%@selectShear1;
elseif sh == 0
She = [0,0];
elseif sh == 1
She = [5,10];%@selectShear2;
end
for sc = [0,-1,1]
if sc == -1
Sca = @selectScale1;
elseif sc == 0
Sca = [1,1];
elseif sc == 1
Sca = @selectScale2;
end
for tl = [0,-1,1]
if tl == -1
Trax = -[Tr2,Tr1];
Tray = -[Tr2,Tr1];
Traz = -[Tr2,Tr1];
elseif tl == 0
Trax = [0,0];
Tray = [0,0];
Traz = [0,0];
elseif tl == 1
Trax = [Tr1,Tr2];
Tray = [Tr1,Tr2];
Traz = [Tr1,Tr2];
end
for zr = 0:1
tform = randomAffine3d(Rotation=Rot,Shear=She,Scale=Sca,XTranslation=Trax,YTranslation=Tray,ZTranslation=Traz);
end
end
end
end
end
function [rotationAxis,theta] = selectRotation1
theta = rand(1,1) * 10+5;
rotationAxis = [1,0,0]';
theta1 = rand(1,1) * 10;
theta2 = rand(1,1) * 10;
% Rz = [cosd(theta2),-sind(theta2),0;sind(theta2),cosd(theta2),0;0,0,1];
Rx = [1,0,0;0,cosd(theta2),-sind(theta2);0,sind(theta2),cosd(theta2)];
Ry = [cosd(theta1),0,sind(theta1);0,1,0;-sind(theta1),0,cosd(theta1)];
rotationAxis = Rx*Ry*rotationAxis;
rotationAxis = rotationAxis(:)';
end
function [rotationAxis,theta] = selectRotation2
theta = rand(1,1) * 10+5;
theta = -theta;
rotationAxis = [1,0,0]';
theta1 = rand(1,1) * 10;
theta2 = rand(1,1) * 10;
% Rz = [cosd(theta2),-sind(theta2),0;sind(theta2),cosd(theta2),0;0,0,1];
Rx = [1,0,0;0,cosd(theta2),-sind(theta2);0,sind(theta2),cosd(theta2)];
Ry = [cosd(theta1),0,sind(theta1);0,1,0;-sind(theta1),0,cosd(theta1)];
rotationAxis = Rx*Ry*rotationAxis;
rotationAxis = rotationAxis(:)';
end
function A = selectShear1
A = -(rand(1,1)*5+5);
end
function A = selectShear2
A = (rand(1,1)*5+5);
end
function A = selectScale1
A = rand(1,1)*(0.09)+0.9;
end
function A = selectScale2
A = rand(1,1)*(0.09)+1.01;
end
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Mads el 24 de Mzo. de 2023
well, the above without comments before the shear function handles

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