Compensate the vector with the last entry

I have a length L vector contains some numbers, I want to compensate this vector to length K, where K > L, with repeating the last entry of the vector. For example, the vector is [2 4 7 3], after compensate, it will be [2 4 7 3 3 3 3 3]. I hope there is an efficient way to do so because I actually have more than 10^4 vectors to compensate.

Thanks,

[Stephen23]

"I hope there is an efficient way to do so because I actually have more than 10^4 vectors to compensate."

Do you really have 1e4 separate vectors stored in the workspace? How did you get them all there?

[mingcheng nie]

sorry for the ambiguity. I have a loop around 10^4 times, where within each loop I will need compensate the vector :)

Answer 1

[Stephen23]

V = [2,4,7,3];
K = 8;
V(end+1:K) = V(end)

V = 1×8

2 4 7 3 3 3 3 3

Answer 2

[Steven Lord]

If you were using release R2023b or later, you could use the paddata function with the Side name-value argument and either the FillValue name-value argument or the Pattern name-value argument with the 'edge' pattern.

x = [2 4 7 3]

x = 1x4

2 4 7 3

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y = paddata(x, 7, Side = 'trailing', Pattern = 'edge')

y = 1x7

2 4 7 3 3 3 3

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Or to show FillValue with a different value:

y = paddata(x, 7, Side = 'trailing', FillValue = -999)

y = 1x7

2 4 7 3 -999 -999 -999

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