How would I remove multiple specific elements from an array.

The elements I want to remove from array B are displayed from r(i). The current code at the bottom only gets rid of one of the values returned from r(i), but it returns 2 values and I need both removed from the array without just removing them specifically at their location incase entering a new data set changes the locations of the elements I am getting rid of. Thanks!

Data = [923 916 932 927 908 931 953 926 919 963];

B = sort(Data,'ascend');

n = numel(B);

xmin = B(1);

xmax = B(n);

Q1 = round(.25*(n+1));

Q3 = round(.75*(n+1));

atQ1 = B(Q1);

atQ3 = B(Q3);

IQR = atQ3 - atQ1;

MO = 1.5*IQR;

for i = 1:length(B)

if B(i) <=(atQ1-MO) || B(i) >=(atQ3+MO)

r(i) = B(i);

disp(r(i));

end

end

g = B(B~=r(i));

display(g);

Answer 1

[Selena Mastrodonato]

If I have understood correctly, you could replace your second-last line of code with B(B==r) = []

Data = [923 916 932 927 908 931 953 926 919 963];
B = sort(Data,'ascend');
n = numel(B);
xmin = B(1);
xmax = B(n);
Q1 = round(.25*(n+1));
Q3 = round(.75*(n+1));
atQ1 = B(Q1);
atQ3 = B(Q3);
IQR = atQ3 - atQ1;
MO = 1.5*IQR;
for i = 1:length(B)
    if B(i) <=(atQ1-MO) || B(i) >=(atQ3+MO)
    
        r(i) = B(i);
        disp(r(i));
        
    end
   
end

   953

   963

B(B==r) = []

B = 1×8

908 916 919 923 926 927 931 932

So that you delete all the elements present in r

[Oliver Ries]

this doesnt seem to be working for me.

[Oliver Ries]

I think what is happening is my for loop finds the first value but then replaces it when it runs again with the next value. How do I save all the values into one array.

Answer 2

[Torsten]

Data = [923 916 932 927 908 931 953 926 919 963];
B = sort(Data,'ascend');
n = numel(B);
xmin = B(1);
xmax = B(n);
Q1 = round(.25*(n+1));
Q3 = round(.75*(n+1));
atQ1 = B(Q1);
atQ3 = B(Q3);
IQR = atQ3 - atQ1;
MO = 1.5*IQR;
g = B(B>(atQ1-MO) & B<(atQ3+MO))

g = 1×8

908 916 919 923 926 927 931 932

[Oliver Ries]

This worked. Its amazing how much more simple this one is.

[Image Analyst]

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Answer 3

[Steven Lord]

I would use the rmoutliers function with the "quartiles" method.

Data = [923 916 932 927 908 931 953 926 919 963];
g2 = sort(rmoutliers(Data, "quartiles"))

g2 = 1×8

908 916 919 923 926 927 931 932