extract row from a cell

Hi! I generated a cell similar to this one:

a = {'home'};
b = {'ball' , 'cake' , 'ice'};
c = {'car','moto'};
d = {'money','supercar','toys'};
e = cell(4,0);
e(1,1:numel(a)) = a;
e(2,1:numel(b)) = b;
e(3,1:numel(c)) = c;
e(4,1:numel(d)) = d

I want to extract from cell "e" the first row consisting of three values.

In the case above, the second row of cell "e" consists of three values, one per column. I want to extract this second row.

Answer 1

[Voss]

a = {'home'};
b = {'ball' , 'cake' , 'ice'};
c = {'car','moto'};
d = {'money','supercar','toys'};
e = cell(4,0);
e(1,1:numel(a)) = a;
e(2,1:numel(b)) = b;
e(3,1:numel(c)) = c;
e(4,1:numel(d)) = d;

% construct a logical matrix the same size as e saying whether each
% corresponding cell of e is non-empty:
e_nonempty = ~cellfun(@isempty,e)

e_nonempty = 4×3 logical array
   1   0   0
   1   1   1
   1   1   0
   1   1   1

% find the first row of e that has three non-empty cells:
row = find(sum(e_nonempty,2) == 3,1)

row = 2

% extract that row of e:
result = e(row,:)

result = 1×3 cell array
    {'ball'}    {'cake'}    {'ice'}