How to open files .ict, .hct. a00, .h00

Dear all,

I have four types of documents, as attached.

Anyone can help e ho to open/view this files?

all the file is images.

[Walter Roberson]

Do the ict files have to do with ICARTT ? https://www.earthdata.nasa.gov/esdis/esco/standards-and-practices/icartt-file-format ?

hct file extension appear to have to do with Symmatic anti-virus live updates

a00 file extension appear to be split ARJ archives

h00 file extension appear to be ARM EEPROM files

[mohd akmal masud]

@Walter Roberson no

[Steven Lord]

Without knowledge of the format used to write data from the files (which may be discoverable if you state what program wrote the files) or something like a Rosetta Stone it's going to be difficult or impossible to interpret the data.

If you want to import the data as raw bytes, you could use the low-level file I/O functions. But that's probably not going to help you if you want to display these as images in a figure window.

For example, without me telling you anything else but just the series of letters, can you tell me what this phrase means? "vaghSad wejvatlh loSmaH Soch"

Answer: It's the number 5,347 written in Klingon, according to section 5.2 of the 1992 edition of The Klingon Dictionary (from Google Play Books.)

If I hadn't told you the answer, how long would it take you to have figured that out?

So what types of files are these? Or what program created them?

[mohd akmal masud]

Its created by SIMIND Monte Carlo program.

[DGM]

The .hxx files are obviously plaintext header files, but I don't know about the format spec for the others.

[Cheng]

I want to know how to save the matrix as a.a00 file?

[Voss]

writematrix(M,'a.a00','FileType','text')

where M is your matrix.

[Cheng]

Thank you

Answer 1

[DGM]

Here.

sz = [128 128 128];

fname = 'point1.ict';
fid = fopen(fname);
data = fread(fid,'*uint16'); % assuming uint
fclose(fid);

% this is blindly devectorized 
% may still be transposed, but i can't tell due to symmetry
% note that data is binarized on a [0 1000] scale in uint16
% so if viewing in a denormalized manner, it'll just appear black
% normalize or rescale it as needed
data = reshape(data,sz); 

View as necessary (it's a 3D volumetric image)

The second image is simply a single-precision 3-channel image (RGB?)

sz = [128 128 3];

fname = 'point1_air_w1.a00';
fid = fopen(fname);
data = fread(fid,'*float'); % assuming uint
fclose(fid);

% this is blindly devectorized 
% may still be transposed, but i can't tell due to symmetry
% note that data is unit-scale single-precision float
data = reshape(data,sz); 

How did I know what the parameters were? I just read the header file and entered those values. Consider the first image. These are the relevant lines:

!total number of images := 128

!matrix size [1] := 128

!matrix size [2] := 128

!matrix size [3] := 128

!number of bytes per pixel := 2

!number format := unsigned integer

And the second file:

!total number of images := 3

!matrix size [1] := 128

!matrix size [2] := 128

!number format := short float

!number of bytes per pixel := 4

You could write a giant pile of regex to extract the relevant information from the headers to allow the images to be processed automatically, but with only two examples and no specifications, I'm not going to assume I know what to expect of the header formatting or the meaning of the fields.

[mohd akmal masud]

Yah, this is what i mean, but i got little error when using this command

sz = [128 128 128];
fname = 'point1.ict';
fid = fopen(fname);
data = fread(fid,'*uint16'); % assuming uint
fclose(fid);
% this is blindly devectorized 
% may still be transposed, but i can't tell due to symmetry
% note that data is binarized on a [0 1000] scale in uint16
% so if viewing in a denormalized manner, it'll just appear black
% normalize or rescale it as needed
data = reshape(data,sz);

Error using reshape
Number of elements must not change. Use [] as one of the size inputs to automatically calculate the appropriate size for that
dimension.

[DGM]

Are you using it on the exact same file, because it tests just fine for me. What is the size of data?

[mohd akmal masud]

128x128x128

[Walter Roberson]

dbstop if error

then run your code. When it stops, show us

which data sz
sz

[mohd akmal masud]

Dear @Walter Roberson and @DGM,

let say my data as attached, then how to open?

I tried as below command but got error

sz = [128 128 128];
fname = 'test_tot_w1.h00';
fid = fopen(fname);
data = fread(fid,'*uint16'); % assuming uint
fclose(fid);
% this is blindly devectorized 
% may still be transposed, but i can't tell due to symmetry
% note that data is binarized on a [0 1000] scale in uint16
% so if viewing in a denormalized manner, it'll just appear black
% normalize or rescale it as needed
data = reshape(data,sz); 

Error using reshape

Number of elements must not change. Use [] as one of the size inputs to automatically calculate the appropriate size for that

dimension.

[DGM]

As that header indicates, the image size should be [128 128 64]

You need to check each header file to determine the image size for the corresponding data file.

If for some reason (e.g. a common sensor resolution) all the page geometries can be assumed identical, then you can possibly use a slack dimension to avoid the lookup each time.

data = reshape(data,128,128,[]); 

That would allow you to reshape any image with 128x128 page geometry, without needing to know how many slices there were.

Otherwise, a more robust automated approach would require parsing the header files.