The image calculation found that they are all black or all white.

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The image calculation found that they are all black or all white.
my coding
img1= imread('SCM Data111.jpg');
img = (-0.18 / (-0.28 / (45.39 /img1 - 1))+1) * 5.3;
imwrite(img, 'n_.jpg');
Can you tell me the reason why the subsequent pictures are all black and how to solve it?

Respuesta aceptada

Walter Roberson
Walter Roberson el 26 de Oct. de 2023
img = (-0.18 / (-0.28 / (45.39 /double(img1) - 1))+1) * 5.3;
When you do calculations with integer datatypes, the results of the calculations are converted to the integer data type.
  3 comentarios
Walter Roberson
Walter Roberson el 26 de Oct. de 2023
Your formula divides by the input, but parts of the input can be 0 (especially where there is black.) That leads to large output values in places -- but also leads to small output values for a lot of the image because the division by the large-valued components comes out small.
filename = 'https://www.mathworks.com/matlabcentral/answers/uploaded_files/1521731/image.jpeg';
img1 = imread(filename);
min(img1(:)), max(img1(:))
ans = uint8 0
ans = uint8 255
img = (-0.18 / (-0.28 / (45.39 /double(img1) - 1))+1) * 5.3;
min(img(:)), max(img(:))
ans = 2.4993
ans = Inf
syms x
Q = @(v) sym(v);
imgs = (-Q(0.18) / (-Q(0.28) / (Q(45.39) /x - 1))+1) * Q(5.3)
imgs = 
fplot(imgs, [0 255])
ir = uint8(rescale(img, 0, 255, 'InputMin', 2.5, 'InputMax', 50));
imshow(ir); colorbar
bozheng
bozheng el 28 de Abr. de 2024
can you tell me why we know the value is 'InputMin', 2.5, 'InputMax', 50 thanks

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Image Analyst
Image Analyst el 28 de Abr. de 2024
img1 is an array so you need to use dot division
img = (-0.18 ./ (-0.28 ./ (45.39 ./ img1 - 1)) + 1) * 5.3;
And double check your parentheses to make sure they're correct. For example is
(45.39 ./ img1 - 1)
supposed to be
((45.39 ./ img1) - 1)
or
(45.39 ./ (img1 - 1))

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