Why my user-defined matlab function returns NaN?

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Ramiro
Ramiro el 14 de Dic. de 2023
Movida: Voss el 14 de Dic. de 2023
I wrote a matlab function but when the input argument vector has only one element, it returns NaN. I checked my code and I think everything is OK.
The W argument is a n x 1 vector or a 1 x n vector of weights that sum 1. However, when W = 1, the function returns NaN.
I think it is a bug of my Matlab version (2023b for Mac Intel).
Thanks in advance for your help.
Ramiro
W = 1;
orn = Orness(W)
orn = 1
function orn = Orness(W)
nW = numel(W);
if nW >= 2
orn = zeros(nW,1);
for j = 1:nW
orn(j) = ((nW-j)/(nW-1))*W(j);
end
orn = sum(orn);
elseif nW == 1
orn = 1;
end
end
  1 comentario
Torsten
Torsten el 14 de Dic. de 2023
I cannot reproduce the behaviour you describe (see above).

Iniciar sesión para comentar.

Respuesta aceptada

Ramiro
Ramiro el 14 de Dic. de 2023
Movida: Voss el 14 de Dic. de 2023
Hi, thank you for the command. My path have two Orness functions (one very old). The script is using that function instead of the new one.
So I made the mistake. I renamed the new function and the problem is fixed.
This solved my issue.
Regards
Ramiro

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