minimum point in nested for loop and using min function..i want to know the value of x for which every row of y has minimum elements please help

clear;clc;close;
u1=1:1:3;
u2=0:0.1:1.1;

for jj=1:length(u1)
   s1=inf;
    for kk=1:length(u2)
        
   
       x(jj,kk)=u1(jj)+u2(kk);
       y=abs(x.^2-2);
      z=min(y,[],2);
     
 
    end
end

Answer 1

[Voss]

clear;clc;close;
u1=1:1:3;
u2=0:0.1:1.1;

for jj=1:length(u1)
    % s1=inf;
    for kk=1:length(u2)
        x(jj,kk)=u1(jj)+u2(kk);
    end
end
x

x = 3x12

1.0000 1.1000 1.2000 1.3000 1.4000 1.5000 1.6000 1.7000 1.8000 1.9000 2.0000 2.1000 2.0000 2.1000 2.2000 2.3000 2.4000 2.5000 2.6000 2.7000 2.8000 2.9000 3.0000 3.1000 3.0000 3.1000 3.2000 3.3000 3.4000 3.5000 3.6000 3.7000 3.8000 3.9000 4.0000 4.1000

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% simpler than nested loops:
x = u1.'+u2

x = 3x12

1.0000 1.1000 1.2000 1.3000 1.4000 1.5000 1.6000 1.7000 1.8000 1.9000 2.0000 2.1000 2.0000 2.1000 2.2000 2.3000 2.4000 2.5000 2.6000 2.7000 2.8000 2.9000 3.0000 3.1000 3.0000 3.1000 3.2000 3.3000 3.4000 3.5000 3.6000 3.7000 3.8000 3.9000 4.0000 4.1000

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y=abs(x.^2-2);
[z,c]=min(y,[],2);
r = 1:numel(z);
idx = sub2ind(size(x),r,c.');
x_min = x(idx)

x_min = 1x3

1.4000 2.0000 3.0000

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[Odette]

you're a blessing!

[Voss]

Thanks!