Represent data with a status bar plot
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Nicolas
el 4 de Mzo. de 2025
Comentada: Nicolas
el 6 de Mzo. de 2025
Hello everyone!
I'm looking for a way to represent my data in the form of a status bar, the colour of which depends on the value.
The end result should look something like this

Does anyone know the function that plots something like this?
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Respuesta aceptada
Voss
el 4 de Mzo. de 2025
t = load('mydata.mat').mydata;
X = repmat(double(t.Time(:)),1,2);
C = repmat(double(t.Data(:)),1,2);
Y = zeros(size(X))+[0 1];
figure('Position',[1 1 900 600])
tiledlayout(2,2)
nexttile
plot(t.Time,t.Data)
xlim(t.Time([1 end]))
title(sprintf('line plot:\nentire timeseries'))
nexttile
plot(t.Time,t.Data)
xlim([0 40])
title(sprintf('line plot:\nzoomed to beginning'))
nexttile
surface(X,Y,C,'EdgeColor','none')
xlim(X([1 end],1))
ylim(Y(1)+[-0.5 1.5])
colorbar
title(sprintf('status-bar plot:\nentire timeseries'))
nexttile
surface(X,Y,C,'EdgeColor','none')
xlim([0 40])
ylim(Y(1)+[-0.5 1.5])
colorbar
title(sprintf('status-bar plot:\nzoomed to beginning'))
4 comentarios
Voss
el 5 de Mzo. de 2025
Here's one approach you can use to add the enumerated data (text objects):
t = load('mydata.mat').mydata;
X = repmat(double(t.Time(:)),1,2);
C = repmat(double(t.Data(:)),1,2);
Z = zeros(size(X));
Y = Z+[0 1];
[G,GID] = findgroups(t.Data);
NG = numel(GID);
XT = zeros(NG,1);
for ii = 1:NG
XT(ii) = mean(t.Time(G == ii));
end
YT = (Y(1,1)+Y(1,2))/2*ones(NG,1);
ST = string(GID);
args = {'HorizontalAlignment','center','Color','w','FontSize',14};
figure('Position',[1 1 900 600],'Color',[0.94,0.94,0.94])
tiledlayout(2,1)
nexttile
surface(X,Y,Z,C,'EdgeColor','none')
text(XT,YT,ST,args{:})
xlim(X([1 end],1))
ylim(Y(1,:)+[-0.5 0.5])
colorbar
title(sprintf('status-bar plot:\nentire timeseries'))
nexttile
surface(X,Y,Z,C,'EdgeColor','none')
text(XT,YT,ST,args{:})
xlim([0 40])
ylim(Y(1,:)+[-0.5 0.5])
colorbar
title(sprintf('status-bar plot:\nzoomed to beginning'))
Más respuestas (1)
Aquatris
el 4 de Mzo. de 2025
You can use bar() function with 'stacked' argument;
y = [30 50 10 10];
barh(1,y,"stacked");
2 comentarios
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