Solving an implicit equation with fzero in a function.
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Allen Hammack
el 14 de Mayo de 2025
Comentada: Allen Hammack
el 14 de Mayo de 2025
I am trying to solve an implicit equation using the fzero command. The implicit function includes a few variables. When I set up the function and fzero command with those variables hard-coded everything works. I can't figure out how to create a function that includes the fzero command, so I can solve my original equation implicitly for different values of the variables. Here are my two functions...
function y = weir_height2(h,weir_height,total_weir_length,total_weir_discharge)
y = (2/3) * sqrt(2 * 32.174) * (0.611 + (0.08 * (h./weir_height))) * total_weir_length * (h.^1.5) - total_weir_discharge;
and
function y = weir_height_all(weir_height,h0,total_weir_length,total_weir_discharge)
fun = @weir_height2;
x0 = h0;
z = fzero(fun,x0);
end
I keep getting different errors. Can someone please help me fix my two functions?
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Matt J
el 14 de Mayo de 2025
fun = @(h) weir_height2(h,weir_height,total_weir_length,total_weir_discharge)
4 comentarios
Steven Lord
el 14 de Mayo de 2025
function y = weir_height_all(weir_height2,h0,total_weir_length,total_weir_discharge)
fun = @(h) weir_height2(h,weir_height,total_weir_length,total_weir_discharge);
%snip
I believe you intend for the fun anonymous function you've defined to call the weir_height2 function. But the first input argument to weir_height_all is named weir_height2, so that anonymous function actually tries to index into that variable. Rename the first input argument of weir_height_all to weir_height instead of weir_height2.
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