sort and eliminate elements
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I have a array of 1XN positive numbers which are very closed numbers. I tried to sort them in rising order by eliminating the non-rising order elements. For example, N=20
and
A=
[4.522119728
5.080599083
5.105557046
5.063978752
5.991930715
5.052086095
6.057840556
5.901693267
5.149232851
4.99253134
5.065569374
5.051748207
5.382426394
5.042862762
4.918077391
5.402468089
5.09548983
5.019724889
5.25911928
5.143977878];
I did a for loop as below:
for i=1:length(A)-1
if A(i+1)<=A(i)
A(i+1)=0;
end
end
ind=find(A==0);
A(ind)=[];
However, if A(1)<A(2) and I eliminate A(1) instead of keeping A(1) as the above for loop does, I may end up keep more elements in A. Therefore, I'll make the above for-loop a function. For instance, as N=5000, I need to make a big for-loop to check from A(i) to A(5000) and look for 5000 answers of new As, then compare the length of new As and keep the longest new As.
Is there other more efficient ways?
Thanks.
2 comentarios
Limei
el 26 de Mayo de 2015
dpb
el 26 de Mayo de 2015
Keeping the most possible elements with result monotonically increasing is simply
B=sort(A); % <chuckles...>
Now, what you're looking for is those remaining if don't reorder but select a subset such that the selected subset is sorted ascending?
Respuestas (1)
Image Analyst
el 27 de Mayo de 2015
You can do it this way:
A=...
[4.522119728
5.080599083
5.105557046
5.063978752
5.991930715
5.052086095
6.057840556
5.901693267
5.149232851
4.99253134
5.065569374
5.051748207
5.382426394
5.042862762
4.918077391
5.402468089
5.09548983
5.019724889
5.25911928
5.143977878];
% Initialize
peakValue = A(1);
rowsToKeep = [];
for row = 1 : length(A)
% Check if this value is more than the prior peak.
if A(row) >= peakValue
% It is greater. Save this row number.
rowsToKeep = [rowsToKeep, row];
% Update the peak value.
peakValue = A(row);
end
end
% Extract only those values that we need.
output = A(rowsToKeep)
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