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Summation with looping

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Daniel
Daniel el 5 de Dic. de 2011
Comentada: OLUBUKOLA ogunsola el 5 de Jun. de 2016
Find ∑((x^)n/n!) for x=1.8 and n=0 to 16.
Okay, my first attempt to do this looked like:
x = 1.8 For(0:16) xs = sum((x^n)/factorial(n)) end
xs
But I received the error: ??? Error: File: imageanalystbs.m Line: 11 Column: 6 Unexpected MATLAB expression.
My line 11 is the one with "For (0:16)"
What am I doing wrong here? Any help is appreciated.

Respuesta aceptada

Paulo Silva
Paulo Silva el 5 de Dic. de 2011
for n=0:16 is the correct syntax, you are also making another error by doing the summation in every iteration, you should instead find all values and do the summation after the loop ends
x = 1.8
xl=zeros(17,1); %preallocation of the storage
for n=0:16
xl(n+1) = ((x^n)/factorial(n)); %save every iteration result
end
xs=sum(xl) %calculate the sum of the iteration results
it can also be done without loops
n=0:16;
xs = sum(((x.^n)./factorial(n))); %notice the dots
  6 comentarios
Daniel
Daniel el 6 de Dic. de 2011
Thank you Paulo! I will give it a try and see what happens. No worries Sean, you were a great help on the last question. :)
OLUBUKOLA ogunsola
OLUBUKOLA ogunsola el 5 de Jun. de 2016
i hope someone will still answer this after a long time. how can i achieve this without the built in function factorial, also ill like x to vary from say , 1 to 1000?

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Más respuestas (1)

Image Analyst
Image Analyst el 6 de Dic. de 2011
I think the problem is in your filename:
"imageanalystbs.m"
That sounds like a horrible name to me.
ImageAnalyst
  2 comentarios
Daniel
Daniel el 6 de Dic. de 2011
Sorry, I don't see a problem?
Salah Saad
Salah Saad el 5 de Mayo de 2015
Editada: Salah Saad el 5 de Mayo de 2015
he's being sarcastic...ish, it still is a weird filename

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