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pca: missing first pc

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Raphael
Raphael on 9 Aug 2015
Edited: Raphael on 9 Aug 2015
Hello community,
using the pca function i face the following problem: i have a data set X of 1000 observations (rows) and a little less variables (columns). The data consists of linear combinations of only two vectors.
if i compute pca(X) i find the coordinates of the second pc in coeff(:,1). The first one is missing.
if i compute pca(X') if find the coordinates of both in coeff(:,1) and coeff(:,2), where coeff(:,2) is equal to coeff(:,1) of pca(X).
best regards and thanks in advance Raphael
  2 Comments
Raphael
Raphael on 9 Aug 2015
Thanks for your answer. I wrote a comment to Sagars post which is roughly the same as yours.

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Accepted Answer

Sagar
Sagar on 9 Aug 2015
Your question is not clear, pca(X) will give coefficient matrix whose first column represents coefficients of the first principal component and so on. You cannot do pca(X') because pca understands rows as observations and columns as variables.
  3 Comments
Raphael
Raphael on 9 Aug 2015
was i ment is this: lets say x is the data matrix where columns are variables and rows are observations. That is when I interpret spectra as variables and its values (all spectra are made with the sample points) as observables.
[pc1 score1] = pca(x)
will give me the expected results. What i computed first was
[pc2 score2] = pca(x')
which was apparently wrong. The thing i'm still wondering about is why i found score2(:,1) = pc1(:,2) moreover i cant find an equivalent for pc1(:,2) in score2. maybe this is just a curios coincident and as i can now compute the right pcs its not that important. But i would like to understand this anyway :D

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