# hi, if i have array=[89 130 150 180...],in 1st iteration i need to perform "1:array(1)",in 2nd iteration i need "array(1)+1 :array(2)",in 3rd iteration i need "array(2)+1 :array(3)" and so on,i tried a lot,plz help me

2 views (last 30 days)
kaavya subramani on 30 Sep 2015
Commented: Walter Roberson on 2 Oct 2015
help plz
kaavya subramani on 30 Sep 2015
how to do it using for loop

Walter Roberson on 30 Sep 2015
Edited: Walter Roberson on 2 Oct 2015
array=[89 130 150 180...]
tarray = [1 array];
for K = 1 : length(tarray)-1
tarray(K):tarray(K+1)
end
##### 2 CommentsShowHide 1 older comment
Walter Roberson on 2 Oct 2015
array=[89 130 150 180...]
tarray = [0 array];
for K = 1 : length(tarray)-1
tarray(K)+1:tarray(K+1)
end

Julia on 30 Sep 2015
Hi,
my suggestion is:
do the first iteration outside the loop, the remaining can be done within:
1:array(1);
% do s.th.
for i=1:size(array)-1
(array(i)+1) : array(i+1);
% do s.th.
end

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