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how do I open files automatically in certain order?(numbers giving me trouble)

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So, say I have these files named 1.0.txt, 1.5.txt, 2.0.txt, 2.5.txt, ... 10.0.txt, 10.5.txt
I am automatically opening the files by loop and do what I have to do with the file.
However, Matlab seems to see the file order starting from the first letter.
There fore, Matlab executes the loop in the order of 1.0.txt, 1.5.txt, 10.0.txt, 10.5.txt, 2.0.txt, 2.5.txt... and so on.
I can I avoid this and make the loop go in the order of 1.0, 1.5, 2.0, 2.5, ... 10.0, 10.5 ?
I am doing fprintf and the order is important for my calculation..

Respuesta aceptada

Stephen23
Stephen23 el 27 de En. de 2016
Editada: Stephen23 el 26 de Abr. de 2021
You can download my FEX submission natsortfiles to sort the files into the order you want:
S = dir(...);
S = natsortfiles(S,'\d+\.?\d*');
for k = 1:numel(S)
F = S(k).name % filename
val = sscanf(F,'%f') % numeric value
...
end
And here are your example strings:
>> X = {'1.0.txt','1.5.txt','10.0.txt','10.5.txt','2.0.txt','2.5.txt'}
X =
'1.0.txt' '1.5.txt' '10.0.txt' '10.5.txt' '2.0.txt' '2.5.txt'
>> natsortfiles(X,'\d+(\.\d+)?')
ans =
'1.0.txt' '1.5.txt' '2.0.txt' '2.5.txt' '10.0.txt' '10.5.txt'
Do you see that my code puts them into the order that you want? That is why in my last answer I told you to use natsortfiles.
EDIT If the files always contain only one decimal values, and these are always the leading characters of the filename, then this will also work:
>> X = {'1.0.txt','1.5.txt','10.0.txt','10.5.txt','2.0.txt','2.5.txt'};
>> N = cellfun(@(s)sscanf(s,'%f'),X);
>> [~,idx] = sort(N);
>> X(idx)
ans =
'1.0.txt' '1.5.txt' '2.0.txt' '2.5.txt' '10.0.txt' '10.5.txt'
  4 comentarios
Alikouider
Alikouider el 24 de En. de 2022
And if I would like to make an action between each file how can I handle it?
Image Analyst
Image Analyst el 24 de En. de 2022
@Alikouider have a nested for loop. Inside get the names of the two files, then do whatever "action" you want to do. See the FAQ:

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Más respuestas (1)

Image Analyst
Image Analyst el 27 de En. de 2016
You're going to have to get the base filename, and parse it to find the number. Try using sscanf() or str2double().

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