How to find indices of value that are greater than zero and less than 5

I want to find the indices of a matrix and I am using this command.

if true
  nhd = find(dist_mat1>0 & dist_mat1<6);
end
It is giving me a single column matrix. Is it possible that it can find the indices of all elements from first row, then second and then third. so that I have output variable index has three rows and each value in row shows the column number only.

like nhd = [1,3,4,7;1,2,3,6,7;1,4]

Is it possible ?

Answer 1

[Star Strider]

This works:

dist_mat1 = randi([0 7], 3, 7);                     % Create Matrix
[RowNrs,ColNrs] = find(dist_mat1>0 & dist_mat1<6);
[RowNrSort, Idx] = sort(RowNrs);
for k1 = 1:max(RowNrs)
    Out{k1} = ColNrs(Idx(RowNrSort == k1));
end

[Arsal15]

Thanks alot for your simple but very useful solution Star Strider.

Can you guide further that how to extract which one is common element in all cell values? Like i got this output so three and six common in first n second so I want to use intersection to take out common elements.

if true
     [3;6]  [2;3;4;5;6]  [1;7]
   %**********************************
 Out = Out';
 for i = 1: length (Out)
   ax(i,:) = Out{i,:}; %%?? Giving error mismatched dimension
   ????????         %%no idea how to use intersection to get common                
                    %%and then set diff to separate out the remaining.
 end
end

[Star Strider]

As always, my pleasure!

[Star Strider]

I am not quite certain what you want to do.

The unique function — possibly with more than one output — could be an option.

[Image Analyst]

If they're all integers, maybe take the histogram and find the bin where the count is the number of arrays you examined, which would mean that number was in each of the arrays you examined.