need help with fibo

good afternoon- im noob for this however
I make this code for fibonacci but I dont know how make the code ask for put in two numbers and make this condition while abs(x(k) / x(k-1) –x(k-1)/ x(k-2)) > 0.001
N=input('escoge un numero\n');
fib=zeros(1,N);
fib(1)=1;
fib(2)=1;
k=3;
while k <= N
fib(k)=fib(k-2)+fib(k-1);
k=k+1;
end
fprintf('The Fibonacci sequence to %d terms is\n',N);
fprintf('%g ',fib);
fprintf('\n');

Respuestas (1)

Image Analyst
Image Analyst el 28 de Feb. de 2016

0 votos

To ask the user for two numbers, try this snippet:
% Ask user for two floating point numbers.
defaultValue = {'45.67', '78.91'};
titleBar = 'Enter a value';
userPrompt = {'Enter floating point number 1 : ', 'Enter floating point number 2: '};
caUserInput = inputdlg(userPrompt, titleBar, 1, defaultValue);
if isempty(caUserInput),return,end; % Bail out if they clicked Cancel.
% Convert to floating point from string.
usersValue1 = str2double(caUserInput{1})
usersValue2 = str2double(caUserInput{2})
% Check for a valid number.
if isnan(usersValue1)
% They didn't enter a number.
% They clicked Cancel, or entered a character, symbols, or something else not allowed.
% Convert the default from a string and stick that into usersValue1.
usersValue1 = str2double(defaultValue{1});
message = sprintf('I said it had to be a number.\nI will use %.2f and continue.', usersValue1);
uiwait(warndlg(message));
end
% Do the same for usersValue2

2 comentarios

carlos landin
carlos landin el 28 de Feb. de 2016
thanks can you help me with this to apply in the code while abs(x(k) / x(k-1) –x(k-1)/ x(k-2)) > 0.001
Image Analyst
Image Analyst el 28 de Feb. de 2016
Well, the 0.001 could be one number, but what other number do you want the user to enter?

Iniciar sesión para comentar.

Categorías

Más información sobre Characters and Strings en Centro de ayuda y File Exchange.

Productos

Etiquetas

Preguntada:

el 28 de Feb. de 2016

Comentada:

el 28 de Feb. de 2016

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by