How do I create a 3D histogram for; x = 1*26, y=1*28, z = 26*28 ?
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I would basically like to bin the the 'z' data into ranges of x and y such as the attached picture:
2 comentarios
Joachim Schlosser
el 21 de Mzo. de 2016
Please attach some sample data and the code you have tried so far.
Respuestas (3)
Walter Roberson
el 21 de Mzo. de 2016
There are also a lot of histogram programs in the File Exchange.
2 comentarios
Walter Roberson
el 21 de Mzo. de 2016
Do you need zooming and data tips? If not then see http://www.mathworks.com/matlabcentral/fileexchange/35274-matlab-plot-gallery-bar-graph-3d
If you do, then see for example http://www.mathworks.com/matlabcentral/fileexchange/45916-3d-colored-bar-plot
Image Analyst
el 22 de Mzo. de 2016
Aaron, give the x and y data as an N by 2 array, then pass in the number of bins in each direction into the poorly named hist3() to create your 2D histogram
counts = hist3([x, y], [26, 28]);
8 comentarios
Image Analyst
el 26 de Mzo. de 2016
Well now you'r totally confusing everybody. We though that the x and y were basically ranges that your data could take. So one data point had both an x coordinate, and a y coordinate. And you wanted 28 bins along the y direction, and 26 bins along the x direction. And then "z" would be the counts of how many data points fell into a certain x,y bins. You don't have any z data yet, before taking the histogram, do you? It's to be computed and is the "count" data. If that's not right, then no one has read your mind correctly, and you'll need to explain better and attach your x, y, and z arrays.
Mike Garrity
el 22 de Mzo. de 2016
histogram2(10+5*randn(1e4,1),3*randn(1e4,1),'FaceColor','flat')
13 comentarios
Image Analyst
el 11 de Abr. de 2023
Movida: Rik
el 14 de Abr. de 2023
You don't need the toolbox to run scatteredInterpolant. You can run it on just a regular 2-D matrix. Here is the main part:
%================================ MAIN PART RIGHT HERE ==============================================
% Create the scattered interpolant. x, y, and gray levels must be column vectors so use (:) to make them column vectors.
% And grayLevels must be double or else an error gets thrown.
F = scatteredInterpolant(xAll(:), yAll(:), double(grayLevelsAll(:)))
% The above line creates an interpolant that fits a surface of the form v = F(x,y).
% Vectors x and y specify the (x,y) coordinates of the sample points.
% v is a vector that contains the sample values associated with the points (x,y).
% Get a grid of points at every pixel location in the RGB image.
[xGrid, yGrid] = meshgrid(1:columns, 1:rows);
xq = xGrid(:);
yq = yGrid(:);
% Evaluate the interpolant at query locations (xq,yq).
vq = F(xq, yq);
fittedImage = reshape(vq, rows, columns);
%================================ END OF MAIN PART ==============================================
grayLevelsAll is the known values of the few locations that you know the values of.
xAll and yAll are your known coordinate values of the locations.
rows and columns are the size of the matrix you want to fill out.
fittedImage is the 2-D array - you don't have to consider it as an image if you don't want to.
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