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how do I generate a binary matrix with specified number of 'ones' in each row & column?

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Is there any algorithm to do that?
  2 comentarios
nafila aytija
nafila aytija el 24 de Mzo. de 2016
H=[1 1 1 0 0 1 1 0 0 0 1 0; 1 1 1 1 1 0 0 0 0 0 0 1;0 0 0 0 0 1 1 1 0 1 1 1; 1 0 0 1 0 0 0 1 1 1 0 1; 0 1 0 1 1 0 1 1 1 0 0 0; 0 0 1 0 1 1 0 0 1 1 1 0]; Each column has 3 ones and each row has 6 ones....

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Respuestas (3)

Walter Roberson
Walter Roberson el 24 de Mzo. de 2016
Because the number might be 1, this process is at least as difficult as the n- Rooks puzzle, the task of placing n chess rooks on a n x n board so that they cannot attack each other. You can find more information about the better studied n-Queens problem (diagonals have to be paid attention to) here
  3 comentarios
Roger Stafford
Roger Stafford el 24 de Mzo. de 2016
That would be impossible Nafila! Two ones in each column with six columns add up to a total of twelve ones, whereas four ones in each row with four rows add up to a total of sixteen ones. That can't be done.
Walter Roberson
Walter Roberson el 24 de Mzo. de 2016
One thing you have not made clear is whether the task is to generate one such matrix at random, or if the task is to generate all such matrices given the parameters of size and number for row and column?

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KSSV
KSSV el 24 de Mzo. de 2016
If you want a matrix where positions of 0, 1 are random. You may try round(rand(m,n)).
  2 comentarios
Walter Roberson
Walter Roberson el 24 de Mzo. de 2016
That will often not have the specified number of 1's in each row and column.
nafila aytija
nafila aytija el 24 de Mzo. de 2016
yes....random will generate the random number of bits.not the specified ones......

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Image Analyst
Image Analyst el 24 de Mzo. de 2016
I think you might mean this:
% Specify 3 1's in each row.
numOnes = 3
% Create a 10 by 10 matrix of false/0's.
rows = 10;
columns = 15;
binaryMatrix = false(rows, columns);
% Go down row by row finding positions for numOnes 1's and assign them
for row = 1 : rows
% Get locations in this row.
oneLocations = randperm(columns, numOnes)
% Assign true/1 to those columns.
binaryMatrix(row, oneLocations) = true;
end
% Print final result to command window
binaryMatrix
  4 comentarios
Image Analyst
Image Analyst el 24 de Mzo. de 2016
Oh wait, reading your comment to Walter it looks like you need the number in each column also to be a specified number. In that case, this code will not guarantee that since they're scrambled on a row-by-row basis and does not take other rows into account so you could have any number from 0 to rows in any given column, not necessarily the specified number you want.
Image Analyst
Image Analyst el 24 de Mzo. de 2016
By the way, for the special case of a square matrix where you want the same number in the rows and columns, you can do that. The concept is called "Latin Square" - you might want to research it.

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