pcolor in R2016a broken when using Intel graphics?

I've run into a problem using 'pcolor' on R2016a. When I run the following:
[x, y] = meshgrid(linspace(0, 1, 200), linspace(0, 1, 200));
pcolor(x, y, ones(size(x)))
I get:
Obviously this is not correct. When I set 'opengl software' the problem goes away. This does not occur when using R2015a on the same laptop, and I believe it might be tied to the integrated graphics on the laptop in question (Intel HD Graphics 5500 on Windows 10 using the latest driver) as it does not occur on a desktop using Nvidia graphics. Is there anything that I can do to fix this problem without resorting to software OpenGL?

4 comentarios

Image Analyst
Image Analyst el 29 de Mzo. de 2016
What are you trying to do? Why do you want pcolor() anyway? Do you know that pcolor() doesn't display the last column and row of your data? Why not use imshow() instead?
SimpleYeti
SimpleYeti el 29 de Mzo. de 2016
1) Display the values of a 2D function limited to a small number of values
2) Because it works with meshgrids
3) Yes
4) imshow doesn't work with meshgrids
Image Analyst
Image Analyst el 29 de Mzo. de 2016
You can use meshgrid() to create two 2D arrays of coordinates (your x and y) that you can use directly in your function to create a 2D image, which you then pass in to imshow(). Do you want an example?
SimpleYeti
SimpleYeti el 29 de Mzo. de 2016
Thank you for the suggestion, but imshow() is of much less utility than pcolor() when the background grid is important information.

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Rick Irons
Rick Irons el 29 de Mzo. de 2016
Editada: Rick Irons el 31 de Mzo. de 2016
This is a known driver issue that Intel has addressed in their recent 4380 driver. One workaround is to use the OpenGL hardware basic mode (“opengl hardwarebasic”). Another option is to disable the align vertex centers property (“h.AlignVertexCenters = 'off'") if it is available for the object demonstrating the issue.

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