how to replace char in array with a double
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Seamus Herriman
el 9 de Ag. de 2016
I am making a program that converts Roman numerals to numerical values. My current code is below.
%%Roman Numeral Conversion
%Declare variables
I=1;
V=5;
X=10;
L=50;
C=100;
D=500;
M=1000;
%input Roman numeral
Roman=input('Roman numeral: ','s')
letters=cellstr(Roman')'
for n=1:length(letters)
if (strcmp(letters(n),'I'))||(strcmp(letters(n),'i'))
letters(n)=1;
elseif (strcmp(letters(n),'V'))||(strcmp(letters(n),'v'))
letters(n)=5;
elseif (strcmp(letters(n),'X'))||(strcmp(letters(n),'x'))
letters(n)=10;
elseif (strcmp(letters(n),'L'))||(strcmp(letters(n),'l'))
letters(n)=50;
elseif (strcmp(letters(n),'C'))||(strcmp(letters(n),'c'))
letters(n)=100;
elseif (strcmp(letters(n),'D'))||(strcmp(letters(n),'d'))
letters(n)=500;
elseif (strcmp(letters(n),'M'))||(strcmp(letters(n),'m'))
letters(n)=1000;
else disp('Not valid entries')
break
end
end
number=sum(letters)
text=sprintf(Roman,'= %d',number)
disp(text)
When I run this, I get the error below when I try to substitute the letter for its corresponding numerical value.
Conversion to cell from double is not possible.
Error in Roman_Numeral_Conversion (line 21)
letters(n)=10;
How can I avoid this problem?
1 comentario
Stephen23
el 20 de Jul. de 2025
Note that you can replace two STRCMP calls:
strcmp(letters(n),'V'))||strcmp(letters(n),'v')
with one STRCMPI call:
strcmpi(letters(n),'V')
Respuesta aceptada
James Tursa
el 9 de Ag. de 2016
You made a cell array with this line:
letters = cellstr(Roman')'
That is why you are getting the conversion error. Make it a double instead. E.g.,
letters = zeros(size(Roman));
Then in your loop, compare with Roman instead of letters. E.g.,
if (strcmp(Roman(n),'I'))||(strcmp(Roman(n),'i'))
letters(n)=1;
elseif (strcmp(Roman(n),'V'))||(strcmp(Roman(n),'v'))
letters(n)=5;
:
etc
However, this is just a character conversion code. You still need to put in logic for when values are added vs subtracted. E.g., your code will give an answer of 11 for 'XI' as well as 'IX' when the latter should be 9.
Más respuestas (1)
Steven Lord
el 20 de Jul. de 2025
Movida: Stephen23
el 21 de Jul. de 2025
Another way to do this would be to set up a vector and use indexing. Let's try it with a valid and an invalid Roman numeral string.
decode('MCMLXXXVI')
decode('DIMS')
function arabic = decode(roman)
values = NaN(1, double('z'));
values('ivxlcdm') = [1, 5, 10, 50, 100, 500, 1000];
roman = char(roman);
arabic = NaN(size(roman));
arabic = values(lower(roman));
if anynan(arabic)
error("Roman numeral string '" + roman + "' contained invalid characters")
end
end
1 comentario
Stephen23
el 21 de Jul. de 2025
Editada: Stephen23
el 21 de Jul. de 2025
+1
The second NaN preallocation can be skipped, the indexing itself will generate the same vector:
decode('MCMLXXXVI')
decode('DIMS')
function vec = decode(roman)
map = NaN(1,+'Z');
map('IVXLCDM') = [1,5,10,50,100,500,1000];
vec = map(roman);
assert(~anynan(vec),'Roman numeral string contained invalid characters')
end
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