Syntax x = fmin('fun',x1,x2)

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work wolf
work wolf el 31 de Ag. de 2016
Comentada: Star Strider el 1 de Sept. de 2016
Syntax
x = fmin('fun',x1,x2)
x = fmin('fun',x1,x2,options)
x = fmin('fun',x1,x2,options,P1,P2, ...)
[x,options] = fmin(...)
are not working by matlab? the message from matlab as follows as:
>> f =@(x) x.^3-2*x-5;
>> x = fmin('f', 0, 2)
Undefined function 'fmin' for input arguments of type 'char'.
Did you mean:
>> x = min('f', 0, 2)
Error using min
MIN with two matrices to compare and a working dimension is not supported.
>> x = fminbnd('f', 0, 2)
Cannot find an exact (case-sensitive) match for 'f'

Respuesta aceptada

Star Strider
Star Strider el 31 de Ag. de 2016
You’re almost there.
This works:
f =@(x) x.^3-2*x-5;
x = fminbnd(f, 0, 2)
x =
816.4968e-003
  18 comentarios
work wolf
work wolf el 1 de Sept. de 2016
Relly , thank you sooooo much
Star Strider
Star Strider el 1 de Sept. de 2016
As always, my pleasure!

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Más respuestas (1)

Walter Roberson
Walter Roberson el 31 de Ag. de 2016
"Note: The fmin function was replaced by fminbnd in Release 11 (MATLAB 5.3). In Release 12 (MATLAB 6.0), fmin displays a warning message and calls fminbnd."
If you are using MATLAB 5.3 or earlier, that is important information for us to know. If you are using something that old, you would use
x = fmin('f', 0, 2)
but you would also have to have created file f.m with content
function y = f(x)
y = x.^3-2*x-5;
  2 comentarios
work wolf
work wolf el 31 de Ag. de 2016
x = fmins('fun',x0)
x = fmins('fun',x0,options)
x = fmins('fun',x0,options,[],P1,P2, ...)
[x,options] = fmins(...)
and
z = fzero('fun',x) z = fzero('fun',x,tol)
z = fzero('fun',x,tol,trace)
z = fzero('fun',x,tol,trace,P1,P2,...)
thankx, if the fmin function was replaced by fminbnd, what were replaced fmins and fzero?
Steven Lord
Steven Lord el 31 de Ag. de 2016
fmins -> fminsearch
fzero -> fzero

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