mydata = importdata('data.txt'); A=mydata;
nRows = size(A, 1);
nColumns = size(A,2);
for i=1: nRows
if (nnz(A(i,:)<3540) == 15)
A(i,:)=[];
end
end

 Respuesta aceptada

José-Luis
José-Luis el 15 de Dic. de 2016

0 votos

You don't need to loop
A(sum(A < 3540, 2) == 15,:) = [];

Más respuestas (1)

Steven Lord
Steven Lord el 15 de Dic. de 2016

0 votos

If you must loop (a requirement of a homework assignment, for instance) inside the loop you should not actually delete the rows of the matrix. Instead record which rows need to be deleted and delete all of them after the loop is complete. Why?
x = 1:10;
n = numel(x);
for k = 1:n
fprintf('x contains %d elements, processing element %d of %d.\n', ...
numel(x), k, n);
if mod(x(k), 2) == 0
x(k) = [];
end
end
In this code you're shortening x every other iteration, and eventually you "walk off the end" of the array. Unlike Bugs Bunny, MATLAB notices immediately. Instead of chopping pieces off the array immediately, identify which pieces need to be removed then remove then once identification is complete.
x = 1:10;
n = numel(x);
toBeDeleted = false(size(x));
for k = 1:n
fprintf('x contains %d elements, processing element %d of %d.\n', ...
numel(x), k, n);
if mod(x(k), 2) == 0
toBeDeleted(k) = true;
end
end
x(toBeDeleted) = []

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el 15 de Dic. de 2016

Respondida:

el 15 de Dic. de 2016

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