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I have a polar plot. Is there a way to label the axes?

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Benjamin Cowen
Benjamin Cowen el 9 de En. de 2017
Comentada: Walter Roberson el 12 de En. de 2017
For the r axis, I would like to label "Energy (eV)" How do I do that?
  1 comentario
Walter Roberson
Walter Roberson el 9 de En. de 2017
Editada: Walter Roberson el 9 de En. de 2017
Oddly, the new polarplot() that creates Polar Axes objects, has no provision for axes labels.
I just now put in an enhancement request for this.

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Respuestas (3)

Steven Lord
Steven Lord el 9 de En. de 2017
In release R2016a or later if you create a polaraxes, either using that function directly or by creating a polarplot, you can get the RAxis property of that polaraxes. The RAxis object has a property named Label that contains a text object, and that text object has a property named String.
ax = polaraxes;
rule = ax.RAxis;
rlabel = rule.Label;
rlabel.String = 'hello world';
You can chain together the property references if you want to make this a two line code:
ax = polaraxes;
ax.RAxis.Label.String = 'dlrow olleh';
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Benjamin Cowen
Benjamin Cowen el 11 de En. de 2017
I have something like this below. All I want to do is label the r-axis with Energy (eV).
figure(3)
polarplot(a,f,'-ob')
hold on
polarplot(a,g,'-or')
hold on
polarplot(aa,ff,'-ok')
hold on
polarplot(aa,gg,'-og')
set(gca,'LineWidth',line_width)
rlim([0 r_scale])
title('YZ Plane')
thetaticks([0 15 30 45 60 75 90 105 120 135 150 165 180 195 210 225 240 255 270 285 300 315 330 345])
ax = gca;
ax.ThetaAxis.TickLabelInterpreter = 'latex';
ax.ThetaTickLabel = {'[010]','','','[011]','','','[001]','','','[0$\overline{1}$1]','','','[0$\overline{1}$0]','','','[0$\overline{1} \overline{1}$]','','','[00$\overline{1}$]','','','[01$\overline{1}$]','','','[0$\overline{1}$ $\overline{1}$]'};
Steven Lord
Steven Lord el 11 de En. de 2017
Try running this. I had to generate some simple a and f data, but it should show the general technique.
a = sort(pi*rand(1, 100));
f = sin(a);
polarplot(a, f, '-ob')
ax = gca;
rruler = ax.RAxis;
rruler.Label.String = 'Energy (eV)';
The rruler.Label object has properties Interpreter and Rotation, among others, so you can customize it even more than simply changing the String.

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Walter Roberson
Walter Roberson el 9 de En. de 2017
polar() is pretty much plot() of pol2cart() behind the scenes. There is no support for r or theta labels. There is the xlabel and ylabel from the underlying axes, but that is not very useful.
So, what you have to do is pick out an axes position in r and theta terms, pol2cart those into x y components, and text() at that position.

Star Strider
Star Strider el 9 de En. de 2017
If you have R2016a or later, use the polarplot function. It gives you the option of specifying the 'RTickLabel' (link) values. That is likely as close as you can get to what you want to do.
You will need to use sprintf and strsplit to create the labels and a cell array to use as the radius labels.
Example:
eV = linspace(0, 10, 5);
eVstr = sprintf('%.1f eV\n', eV);
eVlbl = strsplit(eVstr, '\n');
eVlbl = eVlbl(1:end-1);
The last element of the original ‘eVlbl’ is an empty string that can cause problems with vector length matching, so it is necessary to eliminate it by the second ‘eVlbl’ assignment.
Experiment with it. If you have problems, describe them here. We can help.
  7 comentarios
Star Strider
Star Strider el 11 de En. de 2017
I was specifically suggesting the arguments to your polarplot calls. Do we need those to understand your problem, or will any vectors do for ‘a’, ‘f’ and the rest?
Walter Roberson
Walter Roberson el 12 de En. de 2017
The example Steven http://www.mathworks.com/matlabcentral/answers/319725-i-have-a-polar-plot-is-there-a-way-to-label-the-axes#comment_419725 gave works for me. I would not say that the location or direction it chooses is exactly my first choice. You might want to set the ruler Rotation to 0 or change the font size or something like that.

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