points lying inside a polygon and a circle

How can I find the number of point lies inside both a circle and a polygon (the point should lie in the mutual/overlapping area in between the circle and the polygon) ?

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Matt J
Matt J el 30 de En. de 2017
Editada: Matt J el 25 de Abr. de 2019
If the circle is centered at (x0,y0), with radius R and the polygon has vertices xv,yv, you could do,
count = sum( inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2) )

3 comentarios

KalMandy
KalMandy el 30 de En. de 2017
what is the output of (x-x0).^2+(y-y0).^2<=R^2) ? does it become 1, if the point is inside the circle?
Matt J
Matt J el 30 de En. de 2017
Yes.
KalMandy
KalMandy el 30 de En. de 2017
Thanks a lot!

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Más respuestas (1)

Image Analyst
Image Analyst el 30 de En. de 2017
Did you try
count = 0;
if inpolygon(x,y,xCircle,yCircle) && inpolygon(x,y,xPoly,yPoly)
count = count + 1
end
where you call inpolygon twice, once passing in the circle coordinates and once passing in the polygon coordinates and then ANDing the two results together?

6 comentarios

KalMandy
KalMandy el 30 de En. de 2017
can I use inpolygon for a circle as well?
Image Analyst
Image Analyst el 30 de En. de 2017
Editada: Image Analyst el 30 de En. de 2017
Yes, if you have the coordinates for the perimeter of the circle. If you don't, then see Matt J's formula below. You didn't specify in what form you have information about the circle. You'd put my code in a loop over all (x,y) points that you have.
count = 0;
for k = 1 : length(x)
if inpolygon(x(k),y(k),xCircle,yCircle) && inpolygon(x(k),y(k),xPoly,yPoly)
count = count + 1
end
end
Same for Matt's code - loop over all x,y that you have.
Matt J
Matt J el 30 de En. de 2017
Same for Matt's code - loop over all x,y that you have.
Neither approach requires a loop over x,y. INPOLYGON is vectorized.
You're right. x and y can be a vector of coordinates. Here's a demo:
% Make circle.
x0 = 20;
y0 = 30;
R = 15;
% Plot circle
pos = [x0-R, y0-R, 2*R, 2*R];
rectangle('Position', pos, 'Curvature',[1 1]);
hold on;
% Make polygon
xv = [10, 30, 30, 10, 10];
yv = [40, 40, 5, 5, 40];
plot(xv, yv, 'b-');
grid on;
% Make 60 points for x and y
numPoints = 60;
x = 70 * rand(1, numPoints);
y = 70 * rand(1, numPoints);
plot(x, y, 'r*');
% Now count how many are in both the circle and the polygon.
count = sum(inpolygon(x,y,xv,yv) & ((x-x0).^2+(y-y0).^2<=R^2))
KalMandy
KalMandy el 30 de En. de 2017
I have the radius and the coordinates of the center of the circle. what is given by xCircle,yCircle? Thanks for your response.
hanif hamden
hanif hamden el 25 de Abr. de 2019
If i put (x,y) in geographical coordinate and I want my radius is 10km. How should I do that?

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