Issue when reading csv file using textscan()

I want to read dataset.csv in my program. I have the following code:
filename = 'dataset.csv';
delimiter = '\t';
formatSpec = '%f%f%[^\n\r]';
fileID = fopen(filename,'r');
dataArray = textscan(fileID, formatSpec, 'Delimiter', delimiter, 'ReturnOnError', false);
fclose(fileID);
However, I get this error:
Error using textscan
Invalid file identifier. Use fopen to generate a valid file identifier.
Can someone tell me the issue? I couldn't spot it!!

4 comentarios

Nick
Nick el 15 de Abr. de 2017
Is the .csv file you are trying to open in your current matlab directory?
Try to use the fully qualified file name; something like
filename = 'c:\folder\of\the\file\dataset.csv';
Thank you guys for responding. The dataset is in the same directory. I used the full path and got this error:
Error using textscan
Mismatch between file and format character vector.
Trouble reading 'Numeric' field from file (row number 1, field number 1) ==> # Undirected graph: ../../data/output/lj.ungraph.txt\n
Star Strider
Star Strider el 15 de Abr. de 2017
You need to look at the file in a text editor to see what it contains. Using textscan with the 'HeaderLines' name-value pair seems an attractive option.

Iniciar sesión para comentar.

 Respuesta aceptada

Image Analyst
Image Analyst el 15 de Abr. de 2017

0 votos

You forgot to include the csv file so we're all going to be guessing here until you do. If you want a fast answer, you should attach the csv file so we can see what's wrong with it.
If the delimiter is a tab, then it's not a csv file despite the extension of csv that you incorrectly gave it. So you can't use csvread(). I suggest you try dlmread(). If you have headerlines, dlmread() now lets you specify how many header lines to skip by specifying the proper starting row and column.

Más respuestas (0)

Preguntada:

el 15 de Abr. de 2017

Respondida:

el 15 de Abr. de 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by