Sum five elements before a specific number

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Karoline Qasem
Karoline Qasem el 17 de Jul. de 2017
Comentada: Karoline Qasem el 18 de Jul. de 2017
Hi, I used "findpeaks" to find the IDs of all the peaks in my data. I need for each peak to find the average of five elements before it. the problem is that some of the peaks don't have five elements before it (say the second value is a peak, therefore, there is only one value before it). How can I tell matlab to average whatever is available but not more than 5 elements?
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Image Analyst
Image Analyst el 18 de Jul. de 2017
Editada: Image Analyst el 18 de Jul. de 2017
Please attach your data. I'm puzzled as to why your indexes are not in ascending order. I need to see the data to learn why. When I run it, ID always has increasing index values. In the meantime, check out movmean() to get a filtered vector, then pick out the values of the filtered array at those indexes.
Karoline Qasem
Karoline Qasem el 18 de Jul. de 2017
Editada: Walter Roberson el 18 de Jul. de 2017
The data is very huge and messy. The reason why it is going decending is because I used this:
NP=6;
[pks,ID]= findpeaks(Q,'NPeaks',NP,'SortStr','descend');

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Walter Roberson
Walter Roberson el 18 de Jul. de 2017
data_before = Yourdata(max(1, idx-5) : idx-1)
Note that in the case that idx is 1, this will give the empty result, as "empty" is all of the data that is available before the location.
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Walter Roberson
Walter Roberson el 18 de Jul. de 2017
Editada: Walter Roberson el 18 de Jul. de 2017
T = [nan(5,1); X(:)];
lenT = length(T);
idx = sub2ind([lenT, 1], 5+bsxfun(@plus, ID, -5:-1), ones(length(ID), 5));
result = nanmean( T(idx), 2 );
Karoline Qasem
Karoline Qasem el 18 de Jul. de 2017
Amazing! Thanks a lot!

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