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Automatically update a string in GUIDE textbox

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Jeffrey Alido
Jeffrey Alido el 21 de Jul. de 2017
Comentada: Image Analyst el 28 de Jul. de 2017
I would like to be able to press a button and have the text field of a static textbox automatically update as a variable changes within a function.
I have some timer function:
function stopwatch
global t
for i = 1:10
clc;
t = tic
pause(1)
end
and the GUI callback function for the pushbutton:
function pushbutton1_Callback(hObject, eventdata, handles)
stopwatch
global t
set(handles.text2,'string',t)
but the textbox only updates once the loop is finished. How do I make it so that the textbox is updated automatically continuously?
Thanks!

Respuestas (2)

Stephen23
Stephen23 el 21 de Jul. de 2017
Editada: Stephen23 el 21 de Jul. de 2017
You will need to set the text string inside the loop. For example (untested):
function stopwatch(h)
for k = 1:10
pause(1);
set(h,'string',tic)
end
end
function pushbutton1_Callback(hObject, eventdata, handles)
stopwatch(handles.text2)
or even all in one function:
function pushbutton1_Callback(~, ~, handles)
for k = 1:10
pause(1);
set(handles.text2,'string',tic)
end
end
  1 comentario
Jeffrey Alido
Jeffrey Alido el 21 de Jul. de 2017
Is there a way to do it while keeping the stopwatch function in a separate .m file?

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Image Analyst
Image Analyst el 21 de Jul. de 2017
Have stopwatch take handles as an input and set it in there and call drawnow:
global t
for i = 1:10
clc;
t = tic
handles.text2.String = sprintf('Starting Time = ', t);
drawnow;
pause(1)
end
Not sure that makes sense to use tic though. You're starting 10 timers but saving only the starting time of the very last timer. Why????
  8 comentarios
Jeffrey Alido
Jeffrey Alido el 28 de Jul. de 2017
I'm still a beginner so I am unsure what the code would all look like. Could you help from here?
So far I have my timer.m function:
function timer
for i = 1:15
clc;
i
pause(1)
end
And I'd like to press a pushbutton in the GUI so that a static textbox displays the timer live.
Thanks!
Image Analyst
Image Analyst el 28 de Jul. de 2017
I'd rather not give code for an approach that I don't recommend.

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