Attempted to access x(12); index out of bounds because numel(x)=11.

What's wrong with this line A(n,1)= x(n); ?? I find it perfectly correct.

x = load('S_chest');
y = load('S_abdomen');

for i= 1:length(y)
    w= [y(i)/(x(i)+x(i-1))];
    y(i)= x(i)*w*1+x(i-1)*w*2;
end

[Stelios Fanourakis]

Sorry. Wrong coding

load('S_chest.mat');
load('S_abdomen.mat');

x= 'S_chest.mat';

A=zeros(5955,2);

A(1,1)=x(1);

for n= 2:5955

      A(n,1)= x(n);
      A(n,2)= x(n-1);

end

Answer 1

[Guillaume]

For your first piece of code, nothing guarantees that x is the same length as y.

For your second piece of code, you assign the char array 'S_chest.mat' of length 11 to x (so x(1) is simply 'S', x(2) simply '_', etc.), so of cource accessing x(12) is an error. Not sure what you meant to do.

Answer 2

[Image Analyst]

The code you posted has nothing to do with what is apparently giving the error. x and y are structures returned from load (not arrays), and your code has no "n" index. The error says it all. In

A(n,1)= x(n);

you're passing n equal to 12 and x only has 11 elements. So there is no 12th element of x. Note: this x is different than the structure returned from load().

[Stelios Fanourakis]

I want to put the value of 5953 data out of excel that S_chest.mat contains into the X coefficient. How do I do?

Answer 3

[Stelios Fanourakis]

Yeah. How do I assign all of 5953 data that the S_chest.mat file containts (excel file) to X??

[Image Analyst]

Looks like you've got that figured out since you've accepted an answer. Or do you still have a problem. If you still have a problem, attach the two .mat files.