Error Undefined Function 'shortestpath' for input arguments of type 'double'
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Waseem Hussain
el 24 de Oct. de 2017
Comentada: Walter Roberson
el 25 de Oct. de 2017
So I'm working on this code that needs to find the shortest distance between 2 points. I have labelled all the distances as 1 for now but when I run
path = shortestpath (DG,1,2)
it returns with the error - undefined function......
This is my code
W = [1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1]
DG = sparse ([1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 2 3 8 9 4 3 18 17 1 2 3 4 5 8 9 18 17 20 19 18 13 12 17 16 3 4 23 23 23 23 22 22 22 22], [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 1 19 18 13 12 7 8 13 14 19 18 13 8 7 12 11 14 15 2 3 8 9 10 13 14 7 6 1 2 19 20 9 10 11 12], W)
path = shortestpath (DG,1,2)
Any help would be appreciated
2 comentarios
Star Strider
el 24 de Oct. de 2017
You need to create a digraph object firsty.
However, when I do:
DG = digraph(DG);
path = shortestpath (DG,1,2)
I get this error message:
Error using digraph (line 214)
Adjacency matrix must be square.
I leave that for you to sort.
Respuesta aceptada
Walter Roberson
el 24 de Oct. de 2017
shortestpath() is defined only for graph and digraph objects. You need to use graph() or digraph() to create a graph before you can shortestpath()
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Waseem Hussain
el 25 de Oct. de 2017
2 comentarios
Steven Lord
el 25 de Oct. de 2017
From the documentation for sparse: "S = sparse(i,j,v) generates a sparse matrix S from the triplets i, j, and v such that S(i(k),j(k)) = v(k). The max(i)-by-max(j) output matrix has space allotted for length(v) nonzero elements."
If you want S to be larger than [max(i) max(j)] in size, you can use sparse to do that as well. Read through the remainder of the documentation for sparse for a description of that syntax.
Walter Roberson
el 25 de Oct. de 2017
The 23 is max() of the two sets of indices you give to sparse -- the maximum node number. You can add a couple of lines of code that would calculate it, but since you are already hard-coding all the node number information you might as well hard-code the 23 as well (that is, better would be if you had assigned the indices to variables in different statements.
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