Trouble with using atan in script, output generated by script is not correct.
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I am working on a problem requiring an iterative process involving the use of the atan() function. When I allow the script to run I am getting a number
alphai2 = 6.9389e-018
however, when I copy the line of code into the command window and execute I get the correct answer of 0.001204 (confirmed by calculator). I can't for the life of me figure out where the script is generating that number from. Since it is part of my convergence criteria my while loop is not running more than once.
V=5; %Velocity of flow coming into prop
Radius=12; %Radius of Prop
omegarpm=1200; %Rotational speed
omegarps=1200/60; %rotational speed in rad/s
localradius=5;
PoverD=8;
Clalpha=2*pi();
Clnot=1.2;
blades=2;
chord=0.1;
Vt=omegarps*Radius; %tips speed caused by rotation
lambda=V/Vt;
x=localradius/Radius;
wtVt=0;
cont=1;
i=2;
alphai1=0;
alphai2=0;
wtf=1;
while wtf<2;
alphai1=alphai2;
beta=atan(PoverD/(pi()*x));
wt=wtVt*Vt;
waVt=0.5*(-1*lambda+sqrt(lambda*lambda+4*wtVt*(x-wtVt)));
wa=waVt*Vt;
phi=atan(lambda/x);
alphai2=atan((V+wa)/(omegarps*localradius-wt))-phi
alpha=beta-alphai2-phi;
Cl=Clalpha*alpha+Clnot;
vevt=((lambda+waVt)^2+(x-wtVt)^2)^0.5;
Ve=vevt*Vt;
gamma=0.5*chord*Cl*Ve;
Fprandtl=(2/pi())*cos(exp(-(blades*(1-x)/(2*sin(atan(lambda))))));
wt=blades*gamma/(4*pi()*localradius*Fprandtl);
wtvt=wt*Vt;
cont=alphai2-alphai1;
if cont<0.00001
wtf=2;
end
end
1 comentario
Respuesta aceptada
Image Analyst
el 29 de Abr. de 2012
What are you doing with your calculator? Did you set a break point on that line and actually punch those numbers in? I even tried assuming you thought it was degrees instead of radians and still didn't get your number of 0.001204. Here's the values from your program:
phi =
0.049958395721943
atanInput =
0.050000000000000
atan(0.050000) = 0.049958
alphai2 =
6.938893903907228e-018
(The atan result may be clipped for display.) I'm tending to believe MATLAB rather than what you did with your calculator.
2 comentarios
Más respuestas (1)
Richard Brown
el 29 de Abr. de 2012
Here's what happens.
- alphai2 gets computed
- the variable wt, which alphai2 depends on, gets updated.
- The exit condition is met, but the old value of alphai2 is retained.
If you recompute alphai2 using the updated wt, you get the answer you're getting if you run the single line at the command prompt after running the script.
0 comentarios
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!