how to sort in increasing order using loop?
Mostrar comentarios más antiguos
for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end
6 comentarios
David Goodmanson
el 16 de Dic. de 2017
Hello baiti, what don't you like about this? It's a bubble sort in increasing order and it works.
baiti
el 16 de Dic. de 2017
David Goodmanson
el 16 de Dic. de 2017
It's cleaner to put A = zeros(1,6) at the beginning, so that if you run the script more than once you get a fresh start for A. I put disp(A) at the end as well, so that you can see the results of your efforts.
Image Analyst
el 16 de Dic. de 2017
Why don't you just use the built-in sort() function?
Jan
el 17 de Dic. de 2017
@baiti: It seems like you have a problem running this code. Then it would be useful, if you mention what the problem is. "it wont work on my matlab" does not allow to reconsider, why you are not satisfied.
Manish Kumar
el 26 de Jun. de 2020
Do you want better algorithm than this?
Respuestas (1)
rohan hazarika
el 18 de Sept. de 2020
for i=1:6
A(i)=input('')
end
for i=1:6
for j=1:5
if A(j)>=A(j+1)
B=A(j);
A(j)=A(j+1);
A(j+1)=B;
end
end
end
Categorías
Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!