Circular region in an image
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Sordin
el 15 de En. de 2018
Comentada: Image Analyst
el 18 de Jul. de 2018
I am trying to replace a circular region in one image with the corresponding region in another image. Here is my code so far:
% Sample images:
I=imread('office_1.jpg');
I2=imread('office_5.jpg');
[imageSizeY, imageSizeX,z1] = size(I);
centerX = ceil(imageSizeX/2);
centerY = ceil(imageSizeY/2);
radius = 200;
for i=1:max(imageSizeY,imageSizeX)
if (((centerY+i) - centerY).^2 ...
+ ((centerX+i) - centerX).^2 <= radius.^2)
I(centerY:centerY+i, centerX:centerX+i, :) ...
= I2(centerY:centerY+i, centerX:centerX+i, :);
end
end
imshow(I)
Unfortunately, my code does not work correctly, and instead of a circle the result is a square (corresponding to only one quadrant of the desired circle):
What are the mistakes here? Any explanation is greatly appreciated.
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Respuesta aceptada
Matt J
el 15 de En. de 2018
Editada: Matt J
el 15 de En. de 2018
I don't really follow the logic of your code, but in any case there are much simpler and more efficient approaches, e.g.,
[yy,xx,~]=ndgrid( (1:imageSizeY)-centerY, (1:imageSizeX)-centerX ,1:z1);
map=(yy.^2+xx.^2<=radius^2);
I(map)=I2(map);
3 comentarios
Image Analyst
el 16 de En. de 2018
Editada: Image Analyst
el 16 de En. de 2018
Does this work for his color image?
Más respuestas (2)
Prince Masedi
el 18 de Jul. de 2018
II. Determine the following statistical parameter using Matlab program (Note you must copy and paste your code on the answer booklet. (1. Error variance, 2. Assume X=Rainfall Y=Runoff fill in the table with respective determined square of (X-Xm) where Xm is the mean of X and determine estimated Y termed as Yest.
1 comentario
Image Analyst
el 18 de Jul. de 2018
How does this answer the original question about pasting circular regions into an image?
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