How to plot intensity profile of an image
77 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Viron Gil Estrada
el 22 de Mzo. de 2018
Comentada: Vivek
el 10 de Ag. de 2022
I want to plot the intensity profile of this image. I tried using improfile but I don't really know how it works. Can anyone help?
1 comentario
Walter Roberson
el 22 de Mzo. de 2018
An intensity profile along which direction?
If you want a profile along a horizontal or vertical line then just use array indexing to extract the vector, and then plot it.
Respuesta aceptada
Akira Agata
el 22 de Mzo. de 2018
Like this?
I = imread('Capture.PNG');
x = [0 size(I,2)];
y = [size(I,1)/2 size(I,1)/2];
c = improfile(I,x,y);
figure
subplot(2,1,1)
imshow(I)
hold on
plot(x,y,'r')
subplot(2,1,2)
plot(c(:,1,1),'r')
hold on
plot(c(:,1,2),'g')
plot(c(:,1,3),'b')
5 comentarios
Warid Islam
el 9 de Jul. de 2019
Hi,
How can we plot the intensity profile of the same image along the vertical direction instead of the horizontal direction? Thank you.
Más respuestas (4)
Akira Agata
el 9 de Jul. de 2019
Hi Warid-san,
You can do it by the same way, like the following.
I = imread('Capture.PNG');
% Since size(I,2)/2 = 215.5, I have set the value '215' directly for x
x = [215 215];
y = [0 size(I,1)];
c = improfile(I,x,y);
figure
subplot(2,1,1)
imshow(I);
hold on
plot(x,y,'r')
subplot(2,1,2)
plot(c(:,1,1),'r')
hold on
plot(c(:,1,2),'g')
plot(c(:,1,3),'b')
4 comentarios
Vivek
el 10 de Ag. de 2022
Hi Akira San,How Can you plot the 1D profile of a rectangular region instead of just line ?Tx,vivek
Lorenzo Gentili
el 20 de Ag. de 2019
Hi Akira,
I'm trying to obtain an intesity profile of the image below, but I need more than a line. I would like to have at least 5 vertical line in order to understand how the intesity vary in different point of the image ( lets say the 2 boundaries, the center and 2 point between the boundaries and the center). Is it possible to obtain an unique intensity profile that is the sum of 5 intesity profile obtained by the verical lines ?
Thank you for your help
Lorenzo
4 comentarios
Image Analyst
el 3 de Mzo. de 2022
Editada: Image Analyst
el 3 de Mzo. de 2022
@YOGITAA YOGITAA, here is the code:
verticalProfile = mean(grayImage(:, column1:column2), 2);
horizontalProfile = mean(grayImage(row1:row2, :), 1);
r r
el 15 de Mayo de 2020
Editada: Walter Roberson
el 16 de Mayo de 2020
I have image of a tumor in it and I want to do it the same way https://www.mathworks.com/matlabcentral/answers/389889-how-to-plot-intensity-profile-of-an-image
, but every time the response is
'improfile' requires Image Processing Toolbox.
Error in line (line 4)
c = improfile(I,x,y);
1 comentario
Walter Roberson
el 16 de Mayo de 2020
You need the Image Processing Toolbox to use improfile()
improfile() uses linspace() to create vectors of coordinates between the two endpoints, and uses interp2() to interpolate at the coordinates; it does the interpolation once for each color channel.
The question then becomes what coordinates you should interplate at
fransec
el 9 de Jun. de 2020
Hello everybody,
Anyone knows how to make an image profile like ones you showed, but but along the diagonal of an image?
Thank you so much.
2 comentarios
Walter Roberson
el 9 de Jun. de 2020
[rows, cols, ~] = size(YourImage);
n = min(rows,cols);
prof_diag = improfile(YourImage, [1 n], [1 n]); %diagonal
prof_antidiag = improfile(YourImage, [n 1], [1 n]); %anti-diagonal
Christopher Gordon
el 22 de Feb. de 2021
Hey! Question along the same lines. I have 30 vertical lines across a 1024 column image/matrix. Is there a way that I can interpolate/extrapolate the remaining columns to get the entire image/matrix?
Ver también
Categorías
Más información sobre Surface and Mesh Plots en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!