Why am I getting a parse error at the logical operator &&?
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Kristen O'Mara
el 3 de Mayo de 2018
Comentada: Kristen O'Mara
el 3 de Mayo de 2018
For some reason I am getting a parse error at && which will not allow my code to run.
function [nucleotides] = BMEactivity(m1, m2)
for i = 1:m1(end)
if m1(i) >= && m2(i) >= 0
nucleotides(i) = 'A';
elseif m1(i) < 0 && m2(i) >= 0
nucleotides(i) = 'C';
elseif m1(i) >= 0 && m2(i) < 0
nucleotides = 'G';
elseif m1(i) < 0 && m2(i) < 0
nucleotides(i) = 'T';
else
end
end
end
Also, I'm not quite sure if this is the correct syntax in the for loop for indexing to the last element of the array. It would be ideal if there was one expression that let me index to the end of m1 and m2 simultaneously.
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Star Strider
el 3 de Mayo de 2018
You’re not incrementing the loop.
Try this:
m1 = randi([-1 1], 20, 1); % Create Data
m2 = randi([-1 1], 20, 1); % Create Data
for i = 1:numel(m1)
if m1(i) >= 0 && m2(i) >= 0
nucleotides(i) = 'A';
elseif m1(i) < 0 && m2(i) >= 0
nucleotides(i) = 'C';
elseif m1(i) >= 0 && m2(i) < 0
nucleotides(i) = 'G';
elseif m1(i) < 0 && m2(i) < 0
nucleotides(i) = 'T';
end
end
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Más respuestas (1)
Ameer Hamza
el 3 de Mayo de 2018
In this line
if m1(i) >= (##) && m2(i) >= 0
You forget to write a number at (##).
4 comentarios
Ameer Hamza
el 3 de Mayo de 2018
Editada: Steven Lord
el 3 de Mayo de 2018
Also, consider pre-allocation. For example before for loop, initialize nucleotides with zeros.
nucleotides = zeros(1, numel(m1));
[SL: fixed typo]
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