How can I equate a character to an integer?

I'm trying to write a function to find the summation of an m by n matrix.

if true
  % code
end
m = 3.6
n = 4
if m == true && n == true
for i = 1:m
for j = 1:n
A(i,j) = i + j;
end
end
else 
 disp('both m and n must be positive integers.')
end
end

[madhan ravi]

Integer has to be a number.Give an example of output you need.

[Stephen H]

for example: i'm given m = 3.6 and n = 4. 3.6 is not an integer and will not work. i want to be able to set m and n to any number and then have it output the sum of the matrix.

[Stephen H]

can i implement a function like mod, floor or fix to make it work?

[madhan ravi]

Yes because index cannot be a decimal value

Answer 1

[Image Analyst]

Try this. I do it both your way, and a more MATLABy way with meshgrid that avoids explicit loops.

m = 3 % Rows or y
n = 4 % Columns or x
if rem(m, 1) == 0 && rem(n, 1) == 0 && m >= 1 & n >= 1
  % Double for loop way:
  A = zeros(m, n);
  for row = 1 : m
    for col = 1 : n
      A(row, col) = row + col;
    end
  end
  
  % Vectorized, MATLAB way:
  [C, R] = meshgrid(1 : n, 1 : m)
  B = C + R  
else
  uiwait(errordlg('Both m and n must be positive integers.'))
end
A % Show in command window.

You get

B =
     2     3     4     5
     3     4     5     6
     4     5     6     7
A =
     2     3     4     5
     3     4     5     6
     4     5     6     7

[Stephen H]

Thank you for the help but I'm not even sure what I wrote is the correct way to find the summation. How can I use the floor, mod, or fix function to round off a number like 3.6?

[Image Analyst]

Well if even you don't know what you want, then I certainly don't.

To "round" a number, just pass it in.

results = mod(3.6, 1)
results = rem(3.6, 1)
results = round(3.6, 1)
results = floor(3.6)
results = ceil(3.6)

[Stephen H]

thank you very much, i think i got it now lol

[madhan ravi]

If the answer works accept the answer so that you appreciate the person’s effort and let others know there is a correct answer for the question.