Plotting the area defin

Iluating x & y, I don't want a & b to be always the same as long as 0<=a<=1 & 0<=b<=1. But I have no idea to resolve this issue!!

Respuestas (3)

John D'Errico
John D'Errico el 13 de Oct. de 2018

1 voto

You know how to use meshgrid! In fact, I know that, because you used it in your other question.
So it you want to plot something over all combinations of a and b, then why not use meshgrid? (10000 points in each dimensions will be wild overkill of course.)

5 comentarios

Image Analyst
Image Analyst el 13 de Oct. de 2018
So he can use linspace() to reduce the number of points and get something like this:
numPoints = 50;
a=linspace(0, 1, numPoints);
b=linspace(0, 1, numPoints);
[a, b] = meshgrid(a,b);
x=a.^2-b.^2;
y=a.*b;
plot(x, y, '-', 'LineWidth', 2);
grid on;
xlabel('x', 'FontSize', 20);
ylabel('y', 'FontSize', 20);
Sultan Al-Hammadi
Sultan Al-Hammadi el 13 de Oct. de 2018
The problem is that when evaluating x & y, I don't want a & b to be always the same as long as 0<=a<=1 & 0<=b<=1. But I have no idea to resolve this issue!!
madhan ravi
madhan ravi el 13 de Oct. de 2018
Editada: madhan ravi el 13 de Oct. de 2018
You need to be clear in what you want to do? Still your statement is not clear
John D'Errico
John D'Errico el 13 de Oct. de 2018
Editada: John D'Errico el 13 de Oct. de 2018
As I said, you resolve the issue by using meshgrid. meshgrid generates ALL combinations of the two variables, a & b.
[a,b] = meshgrid(0:.01:1,0:.01:1);
So a and b are now TWO dimensional arrays, here, each of size 101x101. Now compute x and y as directed.
x = a.^2 - b.^2;
y = a.*b;
plot(x,y,'.')
The result is a sort of triangular domain, with curved edges along the top.
Are you asking how to generate the boundary of that domain? From what you have said, I don't think so.
edgeind = convhull(x(:),y(:));
plot(x(edgeind),y(edgeind),'r-')
But you need to understand that when you want to generate all combinations of two variables like this, USE MESHGRID.
Sultan Al-Hammadi
Sultan Al-Hammadi el 14 de Oct. de 2018
Thank you so much, it looks quite right
Bruno Luong
Bruno Luong el 13 de Oct. de 2018
Editada: Bruno Luong el 13 de Oct. de 2018

0 votos

almost right, you need to make a & b oriented in 2 different dimensions (here row for a and column for b)
a=linspace(0,1,101);
b=linspace(0,1,101)'; % <= make a column
x=a.^2-b.^2;
y=a.*b;
plot(x,y,'.b');

4 comentarios

Sultan Al-Hammadi
Sultan Al-Hammadi el 13 de Oct. de 2018
The problem is that when evaluating x & y, I don't want a & b to be always the same. But I have no idea to resolve this issue!!
Bruno Luong
Bruno Luong el 13 de Oct. de 2018
Editada: Bruno Luong el 13 de Oct. de 2018
you do not need to have same a and b, simply make them oriented differently
Sultan Al-Hammadi
Sultan Al-Hammadi el 13 de Oct. de 2018
Is there a way to get it every possible value of a & b, and hence evaluating all possible values of x & y? [for example, a could equal to 0.1 while b=1, etc]
Bruno Luong
Bruno Luong el 13 de Oct. de 2018
Editada: Bruno Luong el 13 de Oct. de 2018
??? x, y are already computed from all combination of a, b with resolutions of 0.01.
So what your question is about? Might be your should slow down think, then ask a real question.
Bruno Luong
Bruno Luong el 13 de Oct. de 2018

0 votos

Or perhaps you want this?
a=linspace(0,1,100)';
b=linspace(0,1,100)';
rect = [a 0+0*a;
1+0*b b;
flip(a) 1+0*a;
0+0*b flip(b)];
a = rect(:,1);
b = rect(:,2);
x=a.^2-b.^2;
y=a.*b;
plot(x,y,'-b');

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