plotting matrix verses vector
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Good evening
I want to plot a frequency vector (x-axes) with a path loss matrix which is 16*16
I tried this but it gives me an error
figure(1);
plot(p.f,H(1,:),
p.f,H(2,:),
p.f,H(3,:),
p.f,H(4,:),
p.f,H(5,:),
p.f,H(6,:),
p.f,H(7,:),
p.f,H(8,:),
p.f,H(9,:),
p.f,H(10,:),
p.f,H(11,:),
p.f,H(12,:),
p.f,H(13,:),
p.f,H(14,:),
p.f,H(15,:),
p.f,H(16,:));
3 comentarios
Stephen23
el 26 de Oct. de 2018
You could just plot the whole matrix like this:
plot(p.f,H.')
Respuestas (2)
Star Strider
el 26 de Oct. de 2018
The easiest solution is likely:
plot(p.f, H)
If ‘H’ is a square matrix, and you want to transpose it, use:
plot(p.f, H.')
instead.
2 comentarios
Star Strider
el 26 de Oct. de 2018
I assumed ‘p.f’ is a vector.
If it a matrix the same size as ‘H’, either of my plot calls will work:
p.f = rand(16);
H = rand(16, 16);
figure
plot(p.f, H)
If not, you will have to choose what vector in ‘p.f’ to plot with. The vector must have 16 elements to plot with your (16x16) matrix.
madhan ravi
el 26 de Oct. de 2018
Editada: madhan ravi
el 26 de Oct. de 2018
An example its possible using loop:
H=rand(16)
p.f = 1:16
figure(1);
for i = 1:length(H)
plot(p.f(1,:),H(i,:))
hold on
end
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