why nanmean error?

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Lilya
Lilya el 24 de Dic. de 2018
Comentada: madhan ravi el 3 de En. de 2019
Hi all,
I am trying to average 3d matrix that have nan values, but I am getting the following error:
Error using nanmean
Too many input arguments.
and the resulted matrix when i used mean function it doesn't show any data
any suggestion?
Thanks u
  1 comentario
Guillaume
Guillaume el 24 de Dic. de 2018
any suggestion?
Clearly, you passed too many inputs to nanmean. Crucially you haven't shown us how you call nanmean so it's difficult to say exactly what you do wrong.
Note that since R2014b (I think), there is no need to use nanmean, the regular mean function can ignore nans.

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Star Strider
Star Strider el 24 de Dic. de 2018
Editada: Star Strider el 24 de Dic. de 2018
You may have your own function or a variable that you named ‘nanmean’.
Run this from a script or your Command Window:
which nanmean -all
If the first result is:
nanmean is a variable.
You have found the problem. The solution is to re-name your function or variable to something that does not overshadow any MATLAB functions, and is meaningful to you.
  6 comentarios
Star Strider
Star Strider el 24 de Dic. de 2018
No worries, and no need to apologise. It is a relatively common belief that most of us are MathWorks employees (‘MathWorkers’). Only those with the blue ‘STAFF’ label by their names actually are. The rest of us are just here for the fun of it!
madhan ravi
madhan ravi el 24 de Dic. de 2018
Second Star Strider.

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madhan ravi
madhan ravi el 24 de Dic. de 2018
Editada: madhan ravi el 24 de Dic. de 2018
If your using 2018b version just use mean with 'omitnan' as a name pair
doc mean % if and only if your using 2018b to use them with n dimensions
  2 comentarios
Lilya
Lilya el 3 de En. de 2019
ok.. thanks a lot!
madhan ravi
madhan ravi el 3 de En. de 2019
Anytime :) , if you find it helpful make sure to accept the answer.

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