Need help with a while loop to take numbers off.
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Alright so I have counting algorithm but i need it to extract elements from an original source and after extracting them and storing I need matlab to discard them so they dont get count again. How do i do this? My code: if true
DATA = [ 60 0 40 -20 40 -40 50 -30 30 -60 0 -30 40 -30 60];
L = length(DATA);
E = [1:L];
N = 1;
while N < L
N = N + 1;
if N < 3
continue
end
X(N) = [abs(DATA(N)-DATA(N-1))];
Y(N) = [abs(DATA(N-1)-DATA(N-2))];
if X < Y
continue
else
RANGE(N) = Y(N);
XMEAN(N) = [.5*(DATA(N-1)+DATA(N-2))]
DATA (N -2) = []
DATA (N-1) = []
N = N - 2
end
for I = N:L
L = L - 2
E(I) = E(I+1);
end
end
end
1 comentario
Nicolo Zaza
el 21 de Jul. de 2012
Respuestas (1)
Image Analyst
el 21 de Jul. de 2012
Editada: Image Analyst
el 21 de Jul. de 2012
Yes, that will delete elements but you're indexing elements and that will change, not to mention the length of your DATA array keeps getting shorter as you delete elements to eventually as N approaches L you'll get an index out of range error.
What are you really trying to do? Can't you just extract arrays and subtract them, and use diff? Or use hist if you want to count values?
data_n = DATA(3:end)
data_nm1 = DATA(2:end-1)
data_nm2 = DATA(1:end-2)
X = abs(data_n - data_nm1)
Y = abs(data_n - data_nm2)
RANGE = y
xMean = 0.5 * (data_nm1 - data_nm2)
% I have no idea what E is supposed to represent.
3 comentarios
Nicolo Zaza
el 21 de Jul. de 2012
Image Analyst
el 21 de Jul. de 2012
Nicolo Zaza
el 21 de Jul. de 2012
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